Take the right angled triangle with sides 13, 12 and 5. sine theta will be 12/13
When sin theta < 0 and cos theta < 0 we are in the third quadrant so sin theta will be -12/13
tan theta = sin theta / cos theta = -5/13 / -12/13 = -5*13 / -12*13 = 5/12
6n−20=−2n+4(1−3n)
Simplify both sides of the equation.
−6n−20=−2n+4(1−3n)
−6n+−20=−2n+(4)(1)+(4)(−3n)(Distribute)
−6n+−20=−2n+4+−12n
−6n−20=(−2n+−12n)+(4)(Combine Like Terms)
−6n−20=−14n+4
−6n−20=−14n+4
Add 14n to both sides.
−6n−20+14n=−14n+4+14n
8n−20=4
Add 20 to both sides.
8n−20+20=4+20
8n=24
Divide both sides by 8.
8n/8 = 24/8
n=3
Answer:
Required solution (a) 
(b) 40.
Step-by-step explanation:
Given,
(a) Let,
Then,
Integrating 
we get,
Differentiate this with respect to y we get,
compairinfg with 
of the given function we get,
Then,
Again differentiate with respect to z we get,
on compairing we get,
(By integrating h'(z)) where C is integration constant. Hence,
(b) Next, to find the itegration,
(5ab-4a-8)-(9ab-5)
Ok just remember that the minus sign before the (9ab-5) is like a minus 1 so it changes the sign inside the bracket...
>>5ab-4a-8-9ab+5
>>-4ab-4a-3
I'm guessing you just have to leave it like that unless there are other parts to the question or whatever but that's that simplified as far as it can be!
