How many 6-digit numbers can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, if repetitions of digits are allowed?
sveta [45]
There are 6 digits. Each digit can take ten different numbers except for the first digit since it cannot be zero.
So:
9 x 10 x 10 x 10 x 10 x 10
900000 numbers.
Another way of thinking about this is to just count up to 999,999. Obviously there are 999,999 different numbers here. But since our number has to have 6 digits in them, we have to delete 99,999 numbers. Thus there are 900,000 different numbers.
7 minutes is the answer but check with the teacher first
Answer:
3rd one and last one
Step-by-step explanation:
First one:
4 × 3 × 4 = 48
Second one:
1 × 2 × 4 = 8
Third one:
2 × 3 × 5 = 30
Fourth one:
2 × 5 × 4 = 40
Fifth one:
2 × 2 × 4 = 16
Process of elimination:
The first one is itself greater than 47 units³, so this is definitely not one of the two;
A combination of the fourth prism and the smallest one as the second will give a volume of 48 units³, which is greater than 47 so this prism is also not one of the two we are looking for;
This leaves the second, third and fifth;
The second and third sum to 38, which is less than 42 so it is not the correct combination;
Similarly, the second and last gives only 24 so it is not the correct combination;
This leaves the only remaining option of the third and fifth;
30 + 16 = 46, which confirms this to be the correct combination.
Formula for the length of x
Answer:
8a + 2b is 14 and b - 2a is 4 1/2
Step-by-step explanation:
divide 8 by 2 to get 4 and multiply 2 times 5 to get 10, then add 10 + 4
If b=5 and a is 1/2 then 5 - 1/2 = 4 1/2
