subtract 9 from 118 then subtract 84.25 from that amount then add 95.
Hey!
Let p = cost of a pen
<span>Let n = cost of a notebook </span>
<span>The info in the question leads to two equations: </span>
<span>1) 2p + 3n = 5.55 </span>
<span>2) p + 2n = 3.50 </span>
<span>Multiply equation 2) by 2 to get the new system of equations </span>
<span>1a) 2p + 3n = 5.55 </span>
<span>2a) 2p + 4n = 7.00 </span>
<span>Subtract equation 1a) from equation 2a) to get </span>
<span>n = 1.45 ...................... that's the cost of one notebook </span>
<span>~~~~~~~~ </span>
<span>To check, you could go on to figure out p, which turns out to be 0.60 . Put in those values of n and p into the original equations to verify.</span>
Hope this helps! ~Nadia~
Hey There.
Hope your well.
2(−3x)(−4x+x−7)
=(2(−3x))(−4x+x+−7)
=(2(−3x))(−4x)+(2(−3x))(x)+(2(−3x))(−7)
=24x^2−6x^2+42x
<u>=18x^2+42x</u>
Hope this helps,
<em>Azumayay</em>
I think that the answer will be c
Example...
4^x = 16
log(4^x) = log(16)
x*log(4) = log(16)
x = log(16) / log(4)
