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omeli [17]
3 years ago
11

How many 6-digit numbers can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, if repetitions of digits are allowed?

Mathematics
1 answer:
sveta [45]3 years ago
6 0
There are 6 digits.  Each digit can take ten different numbers except for the first digit since it cannot be zero.

So:

9 x 10 x 10 x 10 x 10 x 10

900000 numbers.

Another way of thinking about this is to just count up to 999,999.  Obviously there are 999,999 different numbers here.  But since our number has to have 6 digits in them, we have to delete 99,999 numbers.  Thus there are 900,000 different numbers.
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<h2>Hello!</h2>

The answer is:

The quadratic function that fits the given picture is:

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<h2>Why?</h2>

We can solve the problem and find the correct function that fits the curve below by finding which function intercepts the y-axis at -5 (we can see it from the picture), also, we need to look for a function that represents a parabola opening upwards. We need to remember that when a parabola is opening upwards, its quadratic term coefficient is negative.

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The quadratic function that fits the given picture is:

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Note: I have attached a picture for better understanding.

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