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omeli [17]
3 years ago
11

How many 6-digit numbers can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, if repetitions of digits are allowed?

Mathematics
1 answer:
sveta [45]3 years ago
6 0
There are 6 digits.  Each digit can take ten different numbers except for the first digit since it cannot be zero.

So:

9 x 10 x 10 x 10 x 10 x 10

900000 numbers.

Another way of thinking about this is to just count up to 999,999.  Obviously there are 999,999 different numbers here.  But since our number has to have 6 digits in them, we have to delete 99,999 numbers.  Thus there are 900,000 different numbers.
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Answer:

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Step-by-step explanation

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Answer:

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Masja [62]

Answer:

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Step-by-step explanation:

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3. Caclulate Standard deviation:

SD=\sqrt{\frac{{(0.750-0.500)^{2}+(0.750-0.500)^{2}+(0.200-0.500)^{2}+(0.600-0.500)^{2}+(0.200-0.500)^{2}  } }{5} }

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7 0
2 years ago
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Vikentia [17]
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|−∣=7
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∣−∣
= |(-2-5)|
= |-2-5|
= | -7|=7
8 0
2 years ago
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