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omeli [17]
3 years ago
11

How many 6-digit numbers can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, if repetitions of digits are allowed?

Mathematics
1 answer:
sveta [45]3 years ago
6 0
There are 6 digits.  Each digit can take ten different numbers except for the first digit since it cannot be zero.

So:

9 x 10 x 10 x 10 x 10 x 10

900000 numbers.

Another way of thinking about this is to just count up to 999,999.  Obviously there are 999,999 different numbers here.  But since our number has to have 6 digits in them, we have to delete 99,999 numbers.  Thus there are 900,000 different numbers.
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#1
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#2
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In a certain clothing store, 3 shirts and 5 ties cost $60, and 2 shirts and 3 ties cost $39. What is the cost of each shirt?
Dovator [93]
Let shirts be x and ties be y
3x+5y=$60    Equation 1 (Equation 1 will be denoted by *)
2x+3y=$39    Equation 2 (Equation 2 will be denoted by !)
*x2  6x + 10y = $120
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Substitute this value back into one of the original 2 equations:
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3x+(5x3) = 60
3x+15=60
3x=45
x=15

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6 0
3 years ago
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evablogger [386]
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6 0
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Answer:

In Step 1: option D is correct

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Step-by-step explanation:

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