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omeli [17]
3 years ago
11

How many 6-digit numbers can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, if repetitions of digits are allowed?

Mathematics
1 answer:
sveta [45]3 years ago
6 0
There are 6 digits.  Each digit can take ten different numbers except for the first digit since it cannot be zero.

So:

9 x 10 x 10 x 10 x 10 x 10

900000 numbers.

Another way of thinking about this is to just count up to 999,999.  Obviously there are 999,999 different numbers here.  But since our number has to have 6 digits in them, we have to delete 99,999 numbers.  Thus there are 900,000 different numbers.
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(PLEASE ANSWER AM TIMED! WILL MARK RIGHT ANSWER AS BRAINLIEST AND WILL THANK AND RATE!)
olganol [36]

Answer:

<em>Well, Your best answer will be is </em><em>225° rotation. </em><em>Because, The points A' and C' are tilted more than 180 degrees from the origin of rotation. If it were 90 degrees, the A' and C' would have been in the right side. </em><em>So, The best answer will be is 225°. </em>

<em>Hope That Helps!</em>

^{Itsbrazts}

5 0
3 years ago
PLS HELP ASAP 30 POINTS
GaryK [48]
I guess b or d

hope i’m right
7 0
3 years ago
Which of the following choices shows y = (x − 3)^2 − 25 in standard form?
Ksivusya [100]
The answer would be x^2-6x-16

Explanation:
y=(x-3)^2 -25
(x-3)(x-3)-25
x^2-3x-3x+9-25
x^2-6x-16
6 0
2 years ago
If the graph f(x)= 9x^2+37x+41/3x+5 has an oblique asymptote at y=3x+k what is the value of k
ira [324]

Answer:

k=\frac{22}{3}

Step-by-step explanation:

The oblique asymptote of

f(x)=\frac{9x^2+37x+41}{3x+5},

We perform the long division as shown in the attachment.

The quotient is;

3x+\frac{22}{3}

Comparing to 3x+k

Hence the value of k is \frac{22}{3}

6 0
3 years ago
Read 2 more answers
Three of four numbers have a sum of 22. If the average of the four numbers is 8, what is the fourth number ?
KatRina [158]
X+y+z=22

(x+y+z+t)/4=8
subsitute
x+y+z=22
(22+t)/4=8
multiplly by 4
22+t=32
subtract 22
t=10

the fourth number is 10
3 0
3 years ago
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