The standard equation for the circle is:

(x-h)^2+(y-k)^2=r^2, where (h,k) is the center of the circle and r is the radius.

We are given that the center is (5,1) and r=10 so

(x-5)^2+(y-1)^2=100

4 0

3 years ago

Plz i need help walk me through it, thanks

SVETLANKA909090 [29]

Answer:

$p=36^{\circ}$

Step-by-step explanation:

We can prove that a tangent will always be perpendicular to the radius touching it. So, the other angle in the diagram is $90^{\circ}$ .

Because all the angles of a triangle sum to $180^{\circ}$ , we have that $p+54+90=180$ .

We combine like terms on the left side to get $p+144=180$ .

We subtract $144$ on both sides to get $p=36$ .

So, $\boxed{p=36^{\circ}}$ and we're done!

6 0

2 years ago