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Taya2010 [7]
3 years ago
14

Write an equation in slope intercept form for a line that passed through the two points below (-4,7), (8,1)

Mathematics
1 answer:
vichka [17]3 years ago
7 0
Y= -1/2x + 5
Good luck!!!!
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Describe in words a situation that can be represented by 7÷2​
Gelneren [198K]

Answer:

Example: There are 7 packs of candy, but only two people can share it equally.

Step-by-step explanation:

7/2= 3.5. If each person gets 3.5 bags, they both have an equal amount.

6 0
3 years ago
Solve the system by substitution.<br> 4y =<br> 5x -10y =-50
Trava [24]

Answer:

x = -20 ; y =-5

Step-by-step explanation:

Eqn. 1 ----> 4y = x

Eqn. 2 ----> 5x-10y = -50

(Simplifying eqn.2 further)

=>5(x-2y)=-50

=>x-2y=\frac{-50}{5} =-10

(Substituting the value of x from eqn. 1)

=>4y-2y=-10

=>2y=-10

=>y =\frac{-10}{2} =-5

Now, substituting the value of y in eqn. 1 ,

x = 4*(-5)=-20

7 0
3 years ago
56000009x434383985934863
Orlov [11]

Answer:

2.43255071E22

Rounding to the nearest tenth: 2.4

Nearest hundredth: 2.43

Step-by-step explanation:

Hope I helped! :)

6 0
3 years ago
Read 2 more answers
Find the values of x and y that maximize the objective function P=3x+2y for the graph. What is the maximum value?
AURORKA [14]

Answer:

(9, 0)

Step-by-step explanation:

Maximum or minimum value occurs at the Corner. The points given are (0, 8), (5, 4) and (9, 0).

Substitute (0, 8) in the objective function.

We get P = 3(0) + 2(8) = 16

Now for (x , y) = (5, 4)

P = 3(5) + 2(4) = 15 + 8 = 23

At (9, 0) we get P = 3(9) + 2(0) = 27.

Clearly, we have the maximum value at (9, 0).

And the maximum value is 27.

3 0
3 years ago
4 cot theta<br>=<br>tan theta<br>how do I I find the value of quadrant?​
Ray Of Light [21]

Answer:

4cotα=tanα

4(1/tanα)=tanα

(4/tanα)=tanα

cross multiply

=> 4=tan²α

√4=√tan²α

±2=tanα

α=arc( tan) |2|

α=63.4° ( in first quadrant)

and

α=180+63.4=243.4 in the third quadrant

since we also found a negative answer( i.e –2) then α also lies in quadrants where it gives a negative value(i.e second and fourth quadrants)

α=180–63.4=116.6° in the second quadrant

α=360–63.4=296.6 in the fourth quadrant

therefore theta( in my case, alpha) lies in all four quadrants and is equal to:

α=63.4°,243.4°,116.6°and 296.6°

5 0
3 years ago
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