The width of the driveway is 5x-2.
The height of the carport is 6x+1.
We complete polynomial long division for both of these.
For the driveway:
Dividing 5x²+43x-18 by x+9, we first see how many times x will go into 5x². It goes in 5x times; we write this in the division problem above 43x. Multiplying back through,
5x(x+9) = 5x²+45x. This goes below 5x²+43x. We now subtract:
5x²+43x-(5x²+45x)= -2x; this goes below the 45x we wrote earlier. Bring down the -18.
Now we see how many times x goes into -2x; it goes -2 times. This goes beside our 5x in our answer at the top. Multiplying back through,
-2(x+9) = -2x-18. This goes below our -2x-18 we had, and gives us an answer of 5x-2 with a remainder of 0.
For the carport:
To divide 48x³+68x²-8x-3 by 8x²+10x-3, we see how many times 8x² will go into 48x³. It will go 6x times; write this above -8x. Multiplying back through,
6x(8x²+10x-3) = 48x³+60x²-18; write this below 48x³+68x²-8x. Now subtract:
48x³+68x²-8x-(48x³+60x²-18) = 8x²+10x; this goes below our 48x³+60x²-18. Bring down the -3.
Now we want to see how many times 8x² will go into 8x². It goes 1 time; write this beside our 6x at the top. Multiplying back through,
1(8x²+10x-3) = 8x²+10x-3; write this below the 8x²+10x-3 we have already down. When we subtract these, we get a remainder of 0, with our answer up top as 6x+1.
Firstly, we need to find the price of the blanket/bracelet after the 115% increase.
$10 x 1.15 = $15.20
Now for the 5.5% sales tax, which is applied the the new value of $15.20
$15.20 x 0.055 = 0.83
$15.20 + $0.83 = $16.03
The final cost for the blanket/bracelet is %16.03
The mean can be found by adding the two numbers and dividing by 2
let the second number be y
(x + y)/2 = 1/2x + 1
solve for y
multiply each side by 2
x + y = 2(1/2x + 1)
distribute
x + y = x + 2
subtract x on both sides
y = 2
ANSWER: the second number is 2
The rate of change of the size of the diagonal is; 25.2 ft/s
By Pythagoras theorem;
The length, l of a diagonal of a rectangle whose sides have lengths x and y is;
In essence; the length of the diagonal is dependent on the length, x and y of the sides.
Therefore;
(dl/dt)² = (dx/dt)² + (dy/dt)²
where;
- (dx/dt) = 19 ft/s
- (dy/dt) = -15 ft/s
Therefore,
(dl/dt)² = 19² + (-15)²
(dl/dt)² = 361 + 225
dl/dt = √586
dl/dt = 25.2
Therefore, the size of the diagonal is changing at a rate of; 25.2 ft/s.
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