3. Sqrt of 40
4. Sqrt of 148
Distance formula is sqrt of (x-x1)^2+(y-y1)^2
So (-4-2)^2+ (3-5)^2
(-6)^2+(-2)^2
36+4
Sqrt of 40
Do the same process for 4!
Ps don’t forget to keep the square root
Carry out the operation in the brackets and then follow the order of operations and then you can figure out the answer.
18 is the solution.
Answer:
4.50 s
Step-by-step explanation:
The motion of the ball is represented by the following equation:
(1)
where
h(t) is the elevation at time t
2 ft is the initial elevation at t = 0
+70 ft/s is the initial vertical velocity
is the acceleration due to gravity
The green is located at an elevation of -7 feet, so the ball lands on the green when
h(t) = -7
Substituting into (1)

And re-arranging we get

This is a second-order equation in the form

which has solutions
(2)
Here we have:
a = 16
b = -70
c = -9
Substituting into (2) we find the solutions:

The two solutions are:
t = 4.50 s
t = -0.125 s
The second solution is negative, and since negative time has no physical meaning, the only correct solution is
t = 4.50 s
Answer:
Ask your teacher AKA me.
Step-by-step explanation:
I'll see you at school tomorrow.
X/X+5=-2
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