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Zepler [3.9K]
2 years ago
11

Find the exact value

Mathematics
1 answer:
makkiz [27]2 years ago
8 0

Answer:

Step-by-step explanation:

sin({\alpha\over{2}})=\pm\sqrt{{1-cos(\alpha)\over{2}}}\Rightarrow sin({30\over{2}})=+\sqrt{{1-{\sqrt{3}\over{2}}\over{2}}}={\sqrt{{2-\sqrt{3}}}\over{2}}

cos({\alpha\over{2}})=\pm\sqrt{{1+cos(\alpha)}\over{2}}=+\sqrt{{1+{\sqrt{3}\over{2}}\over{2}}}={\sqrt{{2+\sqrt{3}}}\over{2}}

substituting we get:

tg(15)=\sqrt{{2-\sqrt{3}}\over{2+\sqrt{3}}}

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(x+3)*(x+4)*(x+5)*(x+6)+1
Drupady [299]
There is it hope u have a good day

ANSWER:

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Anvisha [2.4K]

Answer:

  see below

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The graph opens upward if the sign of the squared term is positive. If that sign is negative, the graph opens downward. The first three equations open upward; the last opens downward.

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<u>y=2/3(x-5)^2</u>:  A, D

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8 0
3 years ago
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Answer:

Cost of tshirt = £7.29

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6 0
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