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jonny [76]
3 years ago
10

How do you find the x intercepts of a polynomial function with a zero constant?

Mathematics
1 answer:
ki77a [65]3 years ago
5 0
Plug in zero for y. And then do the math to find your answer.
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Elizabeth swims 50 feet in ten seconds. Jesse swims 110 feet in 20 seconds.
erica [24]

Answer: Jesse

Step-by-step explanation:

Elizabeth - 50f/10s

Jesse - 55f/10s

Reagan - 53.3333333/10s

Jesse is the fastest

5 0
3 years ago
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Find the solution of the problem (1 3. (2 cos x - y sin x)dx + (cos x + sin y)dy=0.
lakkis [162]

Answer:

2*sin(x)+y*cos(x)-cos(y)=C_1

Step-by-step explanation:

Let:

P(x,y)=2*cos(x)-y*sin(x)

Q(x,y)=cos(x)+sin(y)

This is an exact differential equation because:

\frac{\partial P(x,y)}{\partial y} =-sin(x)

\frac{\partial Q(x,y)}{\partial x}=-sin(x)

With this in mind let's define f(x,y) such that:

\frac{\partial f(x,y)}{\partial x}=P(x,y)

and

\frac{\partial f(x,y)}{\partial y}=Q(x,y)

So, the solution will be given by f(x,y)=C1, C1=arbitrary constant

Now, integrate \frac{\partial f(x,y)}{\partial x} with respect to x in order to find f(x,y)

f(x,y)=\int\  2*cos(x)-y*sin(x)\, dx =2*sin(x)+y*cos(x)+g(y)

where g(y) is an arbitrary function of y

Let's differentiate f(x,y) with respect to y in order to find g(y):

\frac{\partial f(x,y)}{\partial y}=\frac{\partial }{\partial y} (2*sin(x)+y*cos(x)+g(y))=cos(x)+\frac{dg(y)}{dy}

Now, let's replace the previous result into \frac{\partial f(x,y)}{\partial y}=Q(x,y) :

cos(x)+\frac{dg(y)}{dy}=cos(x)+sin(y)

Solving for \frac{dg(y)}{dy}

\frac{dg(y)}{dy}=sin(y)

Integrating both sides with respect to y:

g(y)=\int\ sin(y)  \, dy =-cos(y)

Replacing this result into f(x,y)

f(x,y)=2*sin(x)+y*cos(x)-cos(y)

Finally the solution is f(x,y)=C1 :

2*sin(x)+y*cos(x)-cos(y)=C_1

7 0
3 years ago
22*26 how to solve ????????
V125BC [204]
22 times 26 equals to 572
3 0
3 years ago
Read 2 more answers
If you take 5 quizzes and get scores of 95%, 95%, 80%, 85%, and 75%, how would you find your mean quiz score?
avanturin [10]

Answer:

The answer is C.

Step-by-step explanation:

Remember, to find the mean of some scores, you must add all the scores together, then you must divide by the number of scores you added. In this case, you would divide by four, because you had four numbers you added to gether.

4 0
3 years ago
Many insects migrate (travel) between their summer and winter homes. The desert locust migrates about 800 miles farther than the
Harman [31]

Answer:

Distance travelled by Monarch butterfly = 2000 miles

Distance travelled by desert locust  = 2800

Distance travelled by pink-spotted hawk moth= 7800 miles

Step-by-step explanation:

Let the distance travelled by Monarch butterfly  be "X" miles

Distance travelled by desert locust is equal to X + 800 miles

Distance travelled by pink-spotted hawk moth is equal to 4X -200 miles

The total distance travelled by the three is equal to 12600 miles

X + X + 800 + 4X -200 = 12600\\6X = 12600 -600\\6X = 12000\\X = 2000

Distance travelled by Monarch butterfly = 2000 miles

Distance travelled by desert locust  = 2000 + 800 = 2800

Distance travelled by pink-spotted hawk moth = 4 * 2000 -200 = 7800 miles

6 0
3 years ago
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