Ask question

Ask question

All categories

4 years ago

10

How do you find the x intercepts of a polynomial function with a zero constant?

1 answer:

ki77a [65]4 years ago

5 0

Plug in zero for y. And then do the math to find your answer.

You might be interested in

5 + (-3) what is the answer

prohojiy [21]

5-3 is 2 the answer is 2

6 0

3 years ago

Read 2 more answers

81 + 2d > 90, d = 2<br> TRUE OR FALSE

telo118 [61]

Answer:

False

Step-by-step explanation:

False because you plug in 2 for d and makes the equation 81 + 2x2 > 90 then it`s just simple math 2x2 is 4 making it 81 + 4 > 90 and the answer is 85 > 90 which is false

4 0

4 years ago

What is the factores form of (2x^2+11x-40)?

Cerrena [4.2K]

${2x}^{2} + 11x - 40 \\ = (2x - 5)(x + 8)$

Hope this helps. - M

7 0

3 years ago

Express the area of a rectangle with length 7ab and width 2a as a monomial.

Lady_Fox [76]

Area of a rectangle is length * width.

7ab * 2a is the same as 7(2) * a(a) * b

7 * 2 = 14
a * a = a²
b = b

Put it all together.

14a²b is your monomial.

5 0

4 years ago

Combine the terms in the given polynomial then evaluate for x=3, and y=-1

Novay_Z [31]

Answer: $xy^2+3x^2y;\text{ -24}$

Explanation:

The given expression is:

$xy+3xy^2-2xy+3x^2y-2xy^2+xy$

Combine like terms

$xy+xy-2xy+3xy^2-2xy^2+3x^2y$

Simplify the resulting expression

$\begin{gathered} 2xy-2xy+3xy^2-2xy^2+3x^2y \\ \\ xy^2+3x^2y \end{gathered}$

Substitute x = 3 and y = -1 into the simplified expression

$\begin{gathered} xy^2+3x^2y \\ \\ 3(-1)^2+3(3)^2(-1) \\ \\ 3(1)+(-27) \\ \\ 3-27 \\ \\ =-24 \end{gathered}$

6 0

1 year ago