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scoundrel [369]
3 years ago
7

Please solve 21=5n-2(n-3)

Mathematics
2 answers:
Stella [2.4K]3 years ago
8 0

21 = 5n-2(n-3)

21 = 5n-2n+6

21-6 = 3n

n=15/3

n=5

grigory [225]3 years ago
3 0
5=n because you multiply -2 times n then -3 then you add -2n with 5n then subtract 6 from both sides and finally divide by 3
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One way to prove this quadrilateral is a square is by calculating the slopes of its sides and the slopes of its diagonals.
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Answer:

Step-by-step explanation:

<h3>To prove quadrilateral is a square:</h3>

a)  Slope of CB

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     \sf \boxed{Slope = \dfrac{y_2-y_1}{x_2-x_1}}

                \sf = \dfrac{3-[-1]}{0-[-3]}\\\\ =\dfrac{3+1}{0+3}\\\\ = \dfrac{4}{3}

  \sf \text{\bf slope of CB = $\dfrac{4}{3}$}

b) D(1,-4)   ; A(4,0)

    Slope \ of \ DA = \dfrac{0-[-4]}{4-1}\\

                          = \dfrac{0+4}{3}\\\

    \sf \text{\bf Slope of DA = $\dfrac{4}{3}$}

Slope of CB = slope of DA

c) C(-3,-1) ; D(1 , -4)

    \sf Slope \ of \ CD =\dfrac{-4-[-1]}{1-[-3]}

                       \sf = \dfrac{-4+1}{1+3}\\\\    = \dfrac{-3}{4}\\

\sf Slope \ of \ CD * Slope of CB =  \dfrac{-3}{4}*\dfrac{4}{3}=-1

So, CD is perpendicular to   CB

d) B(0,3)  ;  D(1,-4)

    Slope \ of \ BD = \dfrac{-4-3}{1-0}\\\\=\dfrac{-7}{1}\\\\=-7

e) C(-3,-1) ; A(4,0)

   \sf Slope \ of \ CA = \dfrac{0-[-1]}{4-[-3]}\\

                       =\dfrac{0+1}{4+3}\\\\=\dfrac{1}{7}

\text{Slope of CA *Slope of BD = $\dfrac{1}{7}$*(-7)}=-1

So, CA is perpendicular to BD

\sf \text{\bf Slope of DA = \dfrac{4}{3}}

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