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Snowcat [4.5K]
3 years ago
15

Change the negative exponent to a positive exponent

Mathematics
1 answer:
Luba_88 [7]3 years ago
3 0

Answer:

\frac{1}{ {6}^{8} }

Step-by-step explanation:

when the is a base raised to a negative power.....put it under 1 and the negative power now becomes a positive power

Example: 5^-2 = 1/5^2

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La caja rectangular que se ilustra en la figura tiene dimensiones de 8° x 6° x 4°. Calcule el ángulo ∅ formado por una diagonal
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Answer:

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Step-by-step explanation:

4 0
3 years ago
Find the value of y in the equation 3/y-2=8
Romashka-Z-Leto [24]
H e r e i s t h e a n s w e r !

8 0
3 years ago
4.2 x 106 – 1.2 x 105 - 2.5 x 105<br> Write in scientific notation
Alik [6]

Answer:

3.83×10^6

5 0
2 years ago
A cardboard box without a lid is to be made with a volume of 4 ft 3 . Find the dimensions of the box that requires the least amo
Blababa [14]

Answer:

<h2><em>2ft by 2ft by 1 ft</em></h2>

Step-by-step explanation:

Total surface of the cardboard box is expressed as S = 2LW + 2WH + 2LH where L is the length of the box, W is the width and H is the height of the box. Since the cardboard box is without a lid, then the total surface area will be expressed as;

S  = lw+2wh+2lh ... 1

Given the volume V = lwh = 4ft³ ... 2

From equation 2;

h = 4/lw

Substituting into r[equation 1;

S = lw + 2w(4/lw)+ 2l(4/lw)

S = lw+8/l+8/w

Differentiating the resulting equation with respect to w and l will give;

dS/dw = l + (-8w⁻²)

dS/dw = l - 8/w²

Similarly,

dS/dl = w  + (-8l⁻²)

dS/dw = w - 8/l²

At turning point, ds/dw = 0 and ds/dl = 0

l - 8/w² = 0 and w - 8/l² = 0

l = 8/w²  and w =8/l²

l = 8/(8/l² )²

l = 8/(64/I⁴)

l = 8*l⁴/64

l = l⁴/8

8l = l⁴

l³ = 8

l = ∛8

l = 2

Hence the length of the box is 2 feet

Substituting l = 2 into the function l = 8/w² to get the eidth w

2 = 8/w²

1 = 4/w²

w² = 4

w = 2 ft

width of the cardboard is 2 ft

Since Volume = lwh

4 = 2(2)h

4 = 4h

h = 1 ft

Height of the cardboard is 1 ft

<em>The dimensions of the box that requires the least amount of cardboard is 2ft by 2ft by 1 ft</em>

8 0
3 years ago
A 15 foot ladder is placed on the top of a wall. The distance from the bottom of the wall to the bottom of the ladder is 7 feet.
kati45 [8]

The height of the wall from the question is 13.27ft

<h3 /><h3>Pythagoras theorem </h3>

The theorem states that the square of the longest side is equal to the sum of square of other two sides.

From the given question

Hypotenuse (ladder length) = 15ft

Adjacent = 7feet

Required

Height of the wall H

According to the theorem

15² = 7² + H²

H² = 225 - 49

H² = 176

H = 13.27feet

Hence the height of the wall from the question is 13.27ft

Learn more on pythagoras theorem here; brainly.com/question/343682

#SPJ1

5 0
2 years ago
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