What a clever sneaky little problem !
There can only be two of them: 1221 and 2112 .
Distribute -3 to parenthasees
-3(r+9)=-3r-27
now we have
-3r-27=-32
add 27 to both sides
-3r+27-27=27-32
-3r+0=-5
-3r=-5
divide both sides by -3
r=-5/-3
r=5/3
The first set:
3x + 2y = 2 ---1)
5x + 4y = 6 ---2)
From 1), multiply all by 2, 6x + 4y = 4 ---3)
3) - 2),
6x + 4y - (5x + 4y) = 6 - 4
6x + 4y - 5x - 4y = 2
x = 2
Sub in x = 2 into 1),
3(2) + 2y = 2
2y = -4
y = -2
(2 , -2)
The second set:
3x + 2y = 2 ---1)
11x + 8y = 10 ---2)
From 1), multiply all by 4, 12x + 8y = 8 ---3)
3) - 2),
12x + 8y - (11x + 8y) = 8 - 10
12x + 8y - 11x - 8y = -2
x = -2
From this x value alone, we can tell that these two linear systems do NOT have the same solution as they meet at different coordinates.
Hope this helped! Ask me if there's any working from here that you don't understand! :)
Answer:
is it possable you can show the graph
Step-by-step explanation:
