<h2>
Answer:</h2>
The total number of handshakes that would happen between the three people are:
3
<h2>
Step-by-step explanation:</h2>
There are three people at a party.
Let they be denoted by A,B and C.
Now, the total number of handshakes that would occur will be denoted by:
AB, AC and BC
where AB denotes that A and B shake hands.
AC denote that A and C shake hands.
and BC denote that B and C shake hands.
Hence, total number of handshakes are:
3
Answer:
3 (28 n - 9)
Step-by-step explanation:
Simplify the following:
-9 (1 - 10 n) - 2 (3 n + 9)
-9 (1 - 10 n) = 90 n - 9:
90 n - 9 - 2 (3 n + 9)
-2 (3 n + 9) = -6 n - 18:
90 n + -6 n - 18 - 9
Grouping like terms, 90 n - 6 n - 18 - 9 = (90 n - 6 n) + (-9 - 18):
(90 n - 6 n) + (-9 - 18)
90 n - 6 n = 84 n:
84 n + (-9 - 18)
-9 - 18 = -27:
84 n + -27
Factor 3 out of 84 n - 27:
Answer: 3 (28 n - 9)
Plug 4 in for every x
(3*4)-4=8
(4^2)-1=15 [(4^2) is 4*4]
(2*(4^2))-15= 15 [because of PEMDAS the exponent comes first and then multiply by 2 then subtract]
Perimeter is the sum of the lengths so add up all the sides from above
8+15+15=38
