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Svetllana [295]
4 years ago
7

Help me please. I’m getting frustrated. I keep writing out the equation wrong and don’t know where I’m messing up Write all solu

tions.

Mathematics
2 answers:
vampirchik [111]4 years ago
5 0

Answer:

Infinite Solutions

Step-by-step explanation:

7(y-4)-2(2y+2)= -32+3y

Use distributive property of multiplication:

7y-28-4y-4= -32+3y

Combine like terms:

-32+3y = -32+3y

Solve

-32+32 = 3y-3y

0 = 0

True: Infinite Solutions

MrMuchimi4 years ago
3 0

Answer:

Infinite Solutions

Step-by-step explanation:

If you distribute the left side of the expression, you will get 3y -32, which is exactly the same as the right side of the equation. Since both lines are the same, that means that they have an infinite amount of solutions. Therefore, the 4th choice is correct.

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I’m pretty sure it’s yes.
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Which is the best estimate of each percent 48% of 199
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95.52 is the correct answer 
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8x3+26x2+19x+3 is divided by 4x+3
ICE Princess25 [194]

Answer:

Remainder=35.25

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8 0
3 years ago
Past records indicate that the probability of online retail orders
Tcecarenko [31]

Answer:

a) Mean = 1.6, standard deviation = 1.21

b) 18.87% probability that zero online retail orders will turn out to be fraudulent.

c) 32.82% probability that one online retail order will turn out to be fraudulent.

d) 48.31% probability that two or more online retail orders will turn out to be fraudulent.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The mean of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

In this problem, we have that:

p = 0.08, n = 20

a. What are the mean and standard deviation of the number of online retail orders that turn out to be fraudulent?

Mean

E(X) = np = 20*0.08 = 1.6

Standard deviation

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{20*0.08*0.92} = 1.21

b. What is the probability that zero online retail orders will turn out to be fraudulent?

This is P(X = 0).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{20,0}.(0.08)^{0}.(0.92)^{20} = 0.1887

18.87% probability that zero online retail orders will turn out to be fraudulent.

c. What is the probability that one online retail order will turn out to be fraudulent?

This is P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{20,1}.(0.08)^{1}.(0.92)^{19} = 0.3282

32.82% probability that one online retail order will turn out to be fraudulent.

d. What is the probability that two or more online retail orders will turn out to be fraudulent?

Either one or less is fraudulent, or two or more are. The sum of the probabilities of these events is decimal 1. So

P(X \leq 1) + P(X \geq 2) = 1

We want P(X \geq 2)

So

P(X \geq 2) = 1 - P(X \leq 1)

In which

P(X \leq 1) = P(X = 0) + P(X = 1)

From itens b and c

P(X \leq 1) = 0.1887 + 0.3282 = 0.5169

P(X \geq 2) = 1 - P(X \leq 1) = 1 - 0.5169 = 0.4831

48.31% probability that two or more online retail orders will turn out to be fraudulent.

4 0
4 years ago
The roots in the equation <img src="https://tex.z-dn.net/?f=x%5E2%2Bbx%2Bc%3D0%5C%5C" id="TexFormula1" title="x^2+bx+c=0\\" alt=
Anuta_ua [19.1K]
We know b = sum of the two roots
= -4 + 2
= -2
therefore b = -2
7 0
4 years ago
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