Let
x = loaves of bread
y = batches of muffins
You must make a system of two equations with two unknowns that describe the problem
3.5x + 2.5y = 17 --- (1)
0.75x + 0.75y = 4.5 --- (2)
Resolving we have
x = 6-y (from (2))
replacing in (1)
3.5 (6-y) + 2.5y = 17
21 - 3.5y + 2.5y = 17
y = 21-17 = 4
Then substituting in (2)
x = 6-y = 6-4 = 2
Answer
Helena could bake:
2 loaves of bread
4 batches of muffins
Answer: x=20/3=6.67
Step-by-step explanation:
To solve proportions, the most useful way is to use [cross multiplication], where we not multiply horizontally but as diagonally.
-----------------------------------------------------------------------------
Given
x:10=9:6
Cross Multiply
9·x=6·10
9x=60
Divide 9 on both sides
9x/9=60/9
x=20/3=6.67
Hope this helps!! :)
Please let me know if you have any questions
Answer:
Women: 448 Men: 560 Children: 1232
Step-by-step explanation:
5+4+11 = 20/2240 = 112
Women = 4 x 112 = 448
Men = 5 x 112 = 560
Children = 11 x 112 = 1232
Total = 1232 + 560 +448 = 2240
X=2h, y=3k
Substitute these values into equations.
y+2x = 4 ------> 3k+2*2h=4 -----> 3k +4h =4
2/y - 3/2x = 1-----> 2/3k -3/(2*2h) = 1 ------> 2/3k - 3/4h =1
We have a system of equations now.
3k +4h =4 ------> 3k = 4-4h ( Substitute 3k in the 2nd equation.)
2/3k - 3/4h =1
2/(4-4h) -3/4h = 1
2/(2(2-2h)) - 3/4h = 1
1/(2-2h) -3/4h - 1=0
4h/4h(2-2h) -3(2-2h)/4h(2-2h) - 4h(2-2h)/4h(2-2h) =0
(4h- 3(2-2h) - 4h(2-2h))/4h(2-2h) = 0
Numerator should be = 0
4h- 3(2-2h) - 4h(2-2h)=0
Denominator cannot be = 0
4h(2-2h)≠0
Solve equation for numerator=0
4h- 3(2-2h) - 4h(2-2h)=0
4h - 6+6h-8h+8h² =0
8h² +2h -6=0
4h² + h-3 =0
(4h-3)(h+1)=0
4h-3=0, h+1=0
h=3/4 or h=-1
Check which
4h(2-2h)≠0
1) h= 3/4 , 4*3/4(2-2*3/4)=3*(2-6)= -12 ≠0, so we can use h= 3/4
2)h=-1, 4(-1)(2-2*(-1)) =-4*4=-16 ≠0, so we can use h= -1, also.
h=3/4, then 3k = 4-4*3/4 =4 - 3=1 , 3k =1, k=1/3
h=-1, then 3k = 4-4*(-1) =8 , 3k=8, k=8/3
So,
if h=3/4, then k=1/3,
and if h=-1, then k=8/3 .
