Answer:
Yes, he is meeting his original goal to be successful.
The critical value is 1.833
Step-by-step explanation:
H0: mu = 300
Ha: mu > 300
The test is a one-tailed test because the alternate hypothesis is expressed using greater than.
Test statistic (t) = (sample mean - population mean) ÷ (sample sd/√n)
sample mean = 335
population mean = 300
sample sd = 50
n = 2×5 = 10
t = (335 - 300) ÷ (50/√10) = 35 ÷ 15.81 = 2.21
Degree of freedom = n-1 = 10-1 = 9
Significance level = 5%
Critical value corresponding to 9 degrees of freedom and 5% significance level is 1.833.
Conclusion:
Reject the null hypothesis because the test statistic 2.21 is greater than the critical value 1.833.
His original goal to be successful is contained in the alternate hypothesis, therefore, he is meeting it.
Answer:
HCF is 4
LCM is 336
Step-by-step explanation:
2/28 , 48
2/14 , 24
2/7 , 12
2/7 , 6
3/7 , 3
7/7 , 1
1 , 1
HCF is 2 × 2 =4
LCM is 2 × 2 × 2 × 2 × 3 × 7 = 336
Answer:
Step-by-step explanation:
The admission to the fair is $5 and the cost per ride is 50 cents.
Let the number of rides that he can go on be x
If one ride costs 50 cents, x rides will cost 50×x = 50x cents. Converting 50 cents to dollar, it becomes 50/100 = $0.5.
So x rides will cost $0.5x
If his parents gave him $20, he will pay $5 to be admitted into the fair. He would be left with 20- 5 = $15
The equation to find how many rides he can go on will be
0.5x = 15
Since one ride costs $0.5
x rides cost $15
x = 15/0.5 = 30
He can go on 30 rides
Step-by-step explanation:
0.2m^3 = 0.0000002 cm^3
