All categories

3 years ago

HIIIIII 2 QUESTIONS IN THE 2 PICS HELP PLS

Mathematics

1 answer:

skelet666 [1.2K]3 years ago

3 0

Answer:

(1)C- Trapezoid

(2)D-20 square feet

Step-by-step explanation:

<u>Question 1</u>

A cross-section of a rectangular pyramid cut perpendicular to the base but not passing through the top will have two parallel sides where one of the sides will be longer. Therefore, the shape which describes the cross-section will be a trapezoid.

<u>Question 2</u>

The base of the Triangle = 5 feet

Height of the Triangle = 8 feet

$\text{Area of a triangle}=\dfrac12 \times $Base \times Height\\=\dfrac12 \times 5 \times 8\\=20 ft^2$

You might be interested in

5x+5y=-30 find the x and y intercept

Masja [62]

<em>The x and y intercept of 5x + 5y = -30 are (-6, 0) and (0, -6) respectively.</em>

<h2 /><h2>Explanation:</h2>

The Standard Form of the equation of a line is given by:

$Ax+By=C \\ \\ A,B,C \ Real \ Constants \ and \ A>0$

So:

$5x+5y=-30$

is written in Standard Form. The x and y intercepts are:

$x-intercept: \ (x,0) \\ \\ y-intercept: \ (0,y)$

So:

FOR X-INTERCEPT:

$Let's \ set: \\ y=0 \\ \\ 5x+5(0)=-30 \\ \\ Isolating \ x: \\ \\ 5x=-30 \\ \\ x=-\frac{30}{5} \\ \\ \boxed{x=-6}$

FOR Y-INTERCEPT:

$Let's \ set: \\ x=0 \\ \\ 5(0)+5y=-30 \\ \\ Isolating \ x: \\ \\ 5y=-30 \\ \\ y=-\frac{30}{5} \\ \\ \boxed{y=-6}$

Finally,<em> the x and y intercept of 5x + 5y = -30 are (-6, 0) and (0, -6) respectively.</em>

<h2>Learn more:</h2>

Parallel lines: brainly.com/question/12169569

#LearnWithBrainly

6 0

3 years ago

How to find a discount percent

adoni [48]

If they give you the total price and the price after the discount you can use this "formula" to solve it p/100=b/a where p is the percentage, a is the total price and b is the price after the discount.

3 0

3 years ago

If 3t-7=5t, then 6t=?<br><br> Explain how you got your answer!

kirill [66]

Answer:

6t = -21

Step-by-step explanation:

3t-7 = 5t simplifies by subtracting 5t on both sides, then adding 7 on both sides:

3t -5t -7 +7 = 5t-5t+7

-2t = 7

t = -7/2

Then 6t = 6*-7/2 = -21

6 0

3 years ago

Read 2 more answers

A rectangle has a length that is three feet more than twice it’s width. If the area of the rectangle is 90 square feet, then alg

Mkey [24]

Answer:

$Length=27feet\\Width=12 feet$

Step-by-step explanation:

Let, the length of the rectangle be 'L'

and, width of the rectangle be 'W'

length=2*Width+3

$L=(2W+3) feet\\\\$

Area of the rectangle= 90 square feet

Area of a rectangle = Length*Width

$90=(2W+3)*W\\\\2W^2+3W=90\\\\2W^2+3W-90=0\\\\$

Using Factorization Method to solve quadratic equation:

$2W^2-12W+15W-90=0$

Taking common from the equation:

$2W(W-12)+15(W-12)=90\\\\(W-12)(2W+15)=0\\\\W-12=0\\\\W=12 feet$

$2W+15=0\\\\2W=-15\\\\W=-7.5 feet$

The Width cannot be negative, therefore Width(W)=12 feet

$Length=2*Width+3\\\\=(12*2)+3\\\\=24+3\\\\=27 feet$

$Length=27feet\\Width=12 feet$

3 0

3 years ago

If a = √3-√11 and b = 1 /a, then find a² - b²

Serga [27]

If $b=\frac1a$ , then by rationalizing the denominator we can rewrite

$b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8$

Now,

$a^2 - b^2 = (a-b) (a+b)$

and

$a - b = \sqrt3 - \sqrt{11} + \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{9\sqrt3 - 7\sqrt{11}}8$

$a + b = \sqrt3 - \sqrt{11} - \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{7\sqrt3 - 9\sqrt{11}}8$

$\implies a^2 - b^2 = \dfrac{\left(9\sqrt3 - 7\sqrt{11}\right) \left(7\sqrt3 - 9\sqrt{11}\right)}{64} = \boxed{\dfrac{441 - 65\sqrt{33}}{32}}$

5 0

1 year ago