6x0=0 I know the answer I did it on my test
Step-by-step explanation:
∠2 and ∠7 are alternate exterior angles so they are equal.
So you can create the equation
40x-48 = 20x+52 Subtract 20x from both sides. Add 48 to both sides.
20x = 100
x = 5
if you need m∠2 Substtute 5 for x in 20x+52
20(5) + 52 = 100 +52 m∠2= 152°
m∠7 40(5) - 48 = 200-48 m∠7= 152°
Answer:
(3x-17)°+(x+40)°+(2x-5)°=180°[sum of angle of triangle]
6x°+18°=180°
6x°=180°-18°
x°=162°÷6°
x°=27°
Again,
=3x-17. 2x-5. x+40°
=3×27-17. =2×27-5. =27+40
=64°. =49°. =67°
Answer:
<em>B.) Kelly got the better deal.</em>
Step-by-step explanation:
