Answer:
The development of a simplified alphabet.
Explanation:
Answer:
The information technology (IT) sector includes companies that produce software, hardware, or semiconductor equipment, and companies that provide internet or related services.
Explanation:
Members of an Agile development team often agrees on what tasks to work on and they do it together. The one possible solution to this challenge is to Have the database developer train the rest of the team so there are fewer handoffs.
Agile development team often works together as a team. They as team discuss the task yo take, when it will take place etc.
This team is all about communication, teamwork, problem-solving etc.
Conclusively, A task should be completed by one member on the team, but the team may choose to pair up when doing the work.
Learn more from
brainly.com/question/24383225
See full question below:
Your agile team only has one person who knows how to develop database software. So the other developers finish their tasks and then wait for their work to be Integrated into the database. This creates a pile of backed up work for the database developer. But it also means that the other developers must either wait or add to the growing pile of database work. What's one possible solution to this challenge?
Select an answer:
Have the database developer train the rest of the team so there are fewer handoffs.
Have the software developers split their time between other teams so they're not as productive
Encourage the database developer to work overtime to catch up with their work.
Create a large batch of work so the database developer can focus on finishing
Answer:
void printC()
{
int i, j;
for (i = 0; i < 4; i++) //i indicate row number. Here we have 5 rows
{
printf("C"); //print C for every row
for (j = 0; j < 6; j++) //j indicate column number. Here we have 7 Rows
{
if (i == 0 || i == 4) //For first and last row
printf("C"); //print 'CCCCCCC'
else if (i = 1|| i= 3) //for Second forth row
printf("C + +"); //print 'C + +'
else if (i = 2) For second row
printf("C +++++"); //print 'C +++++'
else
continue; //to jump to next iteration
}
printf("\n"); // print in next line
}
}
