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Bogdan [553]
3 years ago
11

(PYTHON HOMEWORK)Given the following code snippet, which statement tests to see if all three sets are equal?:

Computers and Technology
1 answer:
wariber [46]3 years ago
8 0

Answer:

Option D is the correct answer to the following question.

Explanation:

The following option is correct because three sets type variable i.e., "fruit", "fruit2", "fruit3" has contain the same values in it and then they ask for the option is correct if the all are equal and in the option c, there is the if statement in which check the condition if the variable "fruit" is equal to the variable "fruit2" and the variable "fruit" is equal to the variable "fruit3".

so, that' why the following option is correct.

The option A is not correct because there is no equal function in python and we use the operator == to check the condition.

The option B is incorrect because we can see that there is not equal to (!=) operator.

The option D is incorrect because we can see that there is an or operator are used which means if any of the conditions is true then, they return either the other condition is false.

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anygoal [31]

Answer:

It we were asked to develop a new data compression tool, it is recommended to use Huffman coding since it is easy to implement and it is widely used.

Explanation:

The pros and the cons of Huffman coding

Huffman coding is one of the most simple compressing encoding schemes and can be implemented easily and efficiently. It also has the advantage of not being patented like other methods (e.g. arithmetic codingfor example) which however are superior to Huffman coding in terms of resulting code length.

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However: for longer texts the savings outweigh the added Huffman table length. One can also agree on a Huffman table to use that isn’t optimized for the exact text to be transmitted but is good in general. In the English language for example the letters “e” and “t” occur most often while “q” and “z” make up the least part of an average text and one can agree on one Huffman table to use that on average produces a good (=short) result. Once agreed upon it doesn’t have to be transmitted with every encoded text again.

One last thing to remember is that Huffman coding is not restricted to letters and text: it can be used for just any symbols, numbers or “abstract things” that can be assigned a bit sequence to. As such Huffman coding plays an important role in other compression algorithms like JPG compression for photos and MP3 for audio files.

The pros and the cons of Lempel-Ziv-Welch

The size of files usually increases to a great extent when it includes lots of repetitive data or monochrome images. LZW compression is the best technique for reducing the size of files containing more repetitive data. LZW compression is fast and simple to apply. Since this is a lossless compression technique, none of the contents in the file are lost during or after compression. The decompression algorithm always follows the compression algorithm. LZW algorithm is efficient because it does not need to pass the string table to the decompression code. The table can be recreated as it was during compression, using the input stream as data. This avoids insertion of large string translation table with the compression data.

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4 years ago
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Answer:

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Explanation:

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5 0
3 years ago
The value of the mathematical constant e can be expressed as an infinite series: e=1+1/1!+1/2!+1/3!+... Write a program that app
LUCKY_DIMON [66]

Answer:

// here is code in c++ to find the approx value of "e".

#include <bits/stdc++.h>

using namespace std;

// function to find factorial of a number

double fact(int n){

double f =1.0;

// if n=0 then return 1

if(n==0)

return 1;

for(int a=1;a<=n;++a)

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return f;

}

// driver function

int main()

{

// variable

int n;

double sum=0;

cout<<"enter n:";

// read the value of n

cin>>n;

// Calculate the sum of the series

  for (int x = 0; x <= n; x++)

  {

     sum += 1.0/fact(x);

  }

  // print the approx value of "e"

    cout<<"Approx Value of e is: "<<sum<<endl;

return 0;

}

Explanation:

Read the value of "n" from user. Declare and initialize variable "sum" to store the sum of series.Create a function to Calculate the factorial of a given number. Calculate the sum of all the term of the series 1+1/1!+1/2!.....+1/n!.This will be the approx value of "e".

Output:

enter n:12

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