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Fynjy0 [20]
3 years ago
5

WILL MARK FOR BRAINIEST!!!! Find the area of the composite shape.

Mathematics
1 answer:
olganol [36]3 years ago
7 0
A=bh
a=bh/2

6x10=60

7x6=42/2=21

Add together: 60+21=81

81 is your final answer
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In the spinner below, what is true about the probability of landing on 1 and the probability of landing on 6?​
Tanzania [10]

Answer:

1/6 for 1 and 1/6 for 6

Step-by-step explanation:

4 0
3 years ago
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Find the distance between<br> (-1, - 3) and (8, – 3).
dimaraw [331]

Answer: d (A,B) = 9

Step-by-step explanation: d(A,B) = √(xB - xA)^2 + (yB - yA)^2

                                              d(A,B) = √(8-(-1))^2 + (-3 - (-3))^2

                                              d(A,B) = √81 + 0    

                                              d(A,B) = 9                                        

5 0
3 years ago
Let represent the number of tires with low air pressure on a randomly chosen car. The probability distribution of is as follows.
Sindrei [870]

Answer:

a) P(X=3) = 0.1

b) P(X\geq 3) =1-P(X

And replacing we got:

P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4

c) P(X=4) = 0.3

d) P(X=0) = 0.2

e) E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2

f) E(X^2)= \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4

And the variance would be:

Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4

And the deviation:

\sigma =\sqrt{2.4} = 1.549

Step-by-step explanation:

We have the following distribution

x      0     1     2   3   4

P(x) 0.2 0.3 0.1 0.1 0.3

Part a

For this case:

P(X=3) = 0.1

Part b

We want this probability:

P(X\geq 3) =1-P(X

And replacing we got:

P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4

Part c

For this case we want this probability:

P(X=4) = 0.3

Part d

P(X=0) = 0.2

Part e

We can find the mean with this formula:

E(X)= \sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2

Part f

We can find the second moment with this formula

E(X^2)= \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4

And the variance would be:

Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4

And the deviation:

\sigma =\sqrt{2.4} = 1.549

4 0
3 years ago
F(x)=14-2x<br> If f(x)=20, find x
mixer [17]

Answer:

x= -3

Step-by-step explanation:

20=14-2x

-14 -14

6 = -2x

÷-2 ÷-2

-3 =x

3 0
3 years ago
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PLSSSS HELP 20 POINTS ! Match each exponential inequality to its percent rate of change.
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50(1.05)t < 100 is 5% growth

150(1.50)t > 500 is 50% growth

50(1.15)t < 150 is 15% growth



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2 years ago
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