The width would be 236 and the lengths would be 118
Use the equations 2L+W=472 and W*L=MAX
Change the first equation to W=472-2L and plug this into the other equation
(472-2L)(L)=MAX
472L-2L^2=M (take derivative)
472-4L=0 (set to 0 to find the max value)
4L=472
L=118
Plug into original to get W=236
Hope this helps!
Answer:
4.8
Step-by-step explanation:
JK is twice as long as LM, so is 4.8 units long.
"Similar" means the sides of one figure have the same ratio as the corresponding sides of the other figure. We see that AB = 2×CD. JK corresponds to AB, and LM corresponds to CD.
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We could bother to calculate that sides of JKLM are 1.2 times as long as the corresponding sides of ABCD, but that is not necessary. We only need to find a convenient ratio between the side we want and some other known side. I like a ratio of 2, because it is easy to double a number. We find AB=2CD, so JK=2LM=2×2.4 = 4.8.
The answer is either x = -1 or x = 4.
Answer:
Step-by-step explanation:
The area of the given figure is 56 sq cm
Step-by-step explanation:
Given,
The figure consists of 5 different diagrams: 4 triangles and a square
Each side of square = 4 cm
Height(h) of the triangle = 5 cm
Base(b) of the triangle = 4 cm
To find the area of the given figure
Formula
Area of square = side × side sq cm
Area of triangle = 
×base × height
So, area of square = 4 ×4 sq cm = 16 sq cm
Area of triangle = ×4×5 sq cm = 10 sq cm
The area of 4 triangles = 10×4 sq cm = 40 sq cm
Hence the area of the given diagram = 40 + 16 sq cm = 56 sq cm
