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DochEvi [55]
3 years ago
8

Is it possible for two numbers to have a difference of 8 and a sum of 1?

Mathematics
1 answer:
topjm [15]3 years ago
7 0

Answer: yes , it is possible

Step-by-step explanation:

Let the first number be x and the second number be y .Then , the sum of the two numbers will be x + y , and their difference will be x - y.

Combining the two , we have :

x + y = 1 ............................... equation 1

x - y = 8 ................................. equation 2

solving the system of linear equation by substitution method. From equation 1 , make x the subject of the formula ,

x = 1 - y ...................... equation 3

Substitute equation 3 into equation 2 ,

1 - y - y = 8

1 - 2y = 8

add 2y to both sides

1 = 8 + 2y

subtract 8 from both sides

1 - 8 = 2y

- 7 = 2y

divide through by 2

y = \frac{-7}{2}

y = - 3.5

substitute y = -3.5 into equation 3 to find the value of x , we have

x = 1 - y

x = 1 - ( - 3.5 )

x = 1 + 3.5

x = 4.5

Let us check :

x + y will be

4.5 + (-3.5) = 1

Also ,

x - y will be

4.5 - (-3.5)

⇒ 4.5 + 3.5 = 8

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3 years ago
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Elementary Algebra Skill
mr_godi [17]

The answer is a = \frac{4}{-3}

Step-by-step explanation:

<em>1. Convert the mixed fraction to an improper fraction</em>

To find the numerator, multiply the denominator by the whole number and add the numerator to it.

The denominator remains the same.

So, 2\frac{2}{3} will be \frac{8}{3}

<em>2. Now the equation is,</em>

\frac{3}{2} a - \frac{4}{3} a = \frac{10}{3} + \frac{8}{3} a

<em>3. Take LCM on both sides. </em>

For the left side, multiply the first fraction by \frac{3}{3} and multiply the second fraction by \frac{2}{2}

\frac{3*3}{2*3} a - \frac{4*3}{3*3} a = \frac{10+8a}{3}

<em>4. Solve by making a the subject</em>

\frac{9a-8a}{6} = \frac{10+8a}{3}

\frac{a}{6} = \frac{10+8a}{3}

\frac{3a}{6} =10+8a

\frac{a}{2} = 10 + 8a

a = 2(10 + 8a)

a = 20 + 16a

a-16a = 20

-15a = 20

a = \frac{20}{-15}

a = \frac{4}{-3}

Therefore, the answer is a = \frac{4}{-3}

Keyword: Equations

Learn more about equations at

  • brainly.com/question/10666510
  • brainly.com/question/4460262
  • brainly.com/question/8955867

#LearnwithBrainly

4 0
3 years ago
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xxTIMURxx [149]
The answer for this is 135
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3 years ago
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PLEASE HELP which is a solution to the equation 6 x + y=4
VladimirAG [237]
Its D. x = 2, y = -8
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3 years ago
The relationship between the length and weight of certain sea turtles can be approximated by the equation L = 0,55 W,
Liono4ka [1.6K]

Answer:

4.55 pounds

Step-by-step explanation:

From the above question , we are told that:

The relationship between the length and weight of certain sea turtles can be approximated by the equation

L = 0.55 W,

where

L is the length in feet

W is the weight in pounds. If a sea turtle is 2.5 feet long, which is closest to its weight?

L = 2.5 feet

Hence,

2.5 = 0.55W

W = 2.5/0.55

W = 4.5454545455 pounds

Approximately, weight of the sea turtle in pounds = 4.55 pounds

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