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3 years ago

Walking across a carpet is an example of charge being transferred by

2 answers:

8 0

Walking across a carpet is an example of charge being transferred by friction. The answer is letter D. The carpet, which is at rest, will resist the motion cause by your walking. This resistive motion d the friction the carpet obtained from you and you from the carpet.

dusya [7]3 years ago

6 0

Answer : The correct answer is- D) Friction.

There are three modes of charging, which are Conduction, induction, and friction.

The static electricity is produced due to the rubbing of one substance with another. This is called charing by friction.

Hence, the correct answer is friction as there is friction between carpet and the feet of person walking over it.

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A hotdog cannon shoots a hotdog straight up in the air with an initial velocity of 30 m/s. How high will the hotdog fly?

Yuri [45]

At its peak height, the hotdog will have no vertical velocity, so that

${v_f}^2-{v_i}^2=2(-g)\Delta y\implies-\left(30\,\dfrac{\mathrm m}{\mathrm s}\right)^2=2\left(-9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)y_{\mathrm{max}}$

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3 years ago

A vector is 0.888 m long and points in a 205 degree direction.

Dmitry_Shevchenko [17]

Answer:

-0.805 m

Explanation:

The x-component of a vector is given by:

$v_x = v cos \theta$

where

v is the magnitude of the vector

$\theta$ is the angle of the vector with respect to the positive x-direction

In this problem we have

v = 0.888 m

$\theta=205^{\circ}$

so we have

$v_x = (0.888 m)(cos 205^{\circ})=-0.805 m$

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4 years ago

Which of the following is not true for atoms?

Rzqust [24]

The first one. They are not made of elements. They are elements

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3 years ago

Read 2 more answers

The microwaves in a certain microwave oven have a wavelength of 12.2 cm. How wide must this oven be so that it will contain five

leva [86]

Answer:

$l = 0.305 \ m$

$f = 3.0*10^{11} \ Hz$

Explanation:

From the question we are told that

The wavelength is $\lambda = 12.2 \ cm = 0.122 \ m$

The number of antinodal planes of the electric field considered is n = 5

The width is mathematically represented as

$l = \frac{ n \lambda}{2}$

$l = \frac{5 * 0.122 }{ 2}$

$l = 0.305 \ m$

Generally the frequency the errors was made is mathematically represented as

$f = \frac{c}{\lamda_k}$

Here c is the speed of light with value $c = 3.0*10^{8} \ m/s$

$\lambda_k$ is the wavelength of the microwave has to be in order for there still to be five antinodal planes of the electric field along the width of the oven, which is mathematically represented as