A hotdog cannon shoots a hotdog straight up in the air with an initial velocity of 30 m/s. How high will the hotdog fly?

Physics

1 answer:

Yuri [45]3 years ago

7 0

At its peak height, the hotdog will have no vertical velocity, so that

${v_f}^2-{v_i}^2=2(-g)\Delta y\implies-\left(30\,\dfrac{\mathrm m}{\mathrm s}\right)^2=2\left(-9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)y_{\mathrm{max}}$

$\implies y_{\mathrm{max}}=46\,\mathrm m$

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