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deff fn [24]
4 years ago
13

Periodic waves spread out over the surface of a lake where two women, Jenny and Melissa, are fishing in separate boats 46 meters

apart. Each woman's boat bobs up and down 26/min. At a time when Jenny's boat is at a crest, Melissa's boat is at its lowest point, and there are 4 additional crests between them. Calculate the wavelength of these water waves.
Physics
1 answer:
Tatiana [17]4 years ago
8 0

Answer:

The wavelength of the water is \lambda = 10.22 m

Explanation:

From the question awe are told that

                The distance between the two boats are 46 m

   Now we are told that a the time the Jenny's boat is at a crest,Melissa's boat is at its lowest point, and there are 4 additional crests between them which can be mathematically represented as

                         Number of wavelength = 4 + 0.5(this accounts for the difference in position crest and lowest point)

                                                              = 4.5

Now the wavelength of the water is \lambda = \frac{Distance }{Number \ of \ division }

                                                                 = \frac{46}{4.5} =10.22m

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The kinematics and conservation of momentum relationships allow to find the results for the questions about the measurements and conditions to know the accident conditions are:

     1) The principles of conservation of momentum  and kinematics.

     2)  \theta = tan^{-1} \frac{P_{01}}{p_{02}}

     3) The factors that influence the direction and distance traveled are:

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1) Kinematics studies the movement of bodies, they look for relationships between position, speed and acceleration.

To analyze the accident, you must answer a question such as what speed the vehicles had before the accident, this is the initial speed of each one and their directions.

When reviewing the kinematics relationships we have.

        v^2 = v_o^2 - 2 a x  

Where the acceleration is given by Newton's second law.

        fr = m a

The friction force is given by the expression.

       fr = μ N  

       fr = μ mg

       

Let's Substitute.

         μ m g = m a

         a = μ g

The friction coefficient is tabulated, for different types of rubber, pavement and wet,  dry conditions, etc.

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Where this is a vector expression, which in general is solved with the components of each directional.

Consequently to answer the questions you must use the principles of conservation of momentum  and kinematics.

2) If the vehicles travel at right angles and their masses are similar, the direction after the collision  in each direction.

           tan \theta = \frac{p_{01}}{p_{02}}  

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3) The factors that influence the direction and distance traveled are:

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