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deff fn [24]
3 years ago
13

Periodic waves spread out over the surface of a lake where two women, Jenny and Melissa, are fishing in separate boats 46 meters

apart. Each woman's boat bobs up and down 26/min. At a time when Jenny's boat is at a crest, Melissa's boat is at its lowest point, and there are 4 additional crests between them. Calculate the wavelength of these water waves.
Physics
1 answer:
Tatiana [17]3 years ago
8 0

Answer:

The wavelength of the water is \lambda = 10.22 m

Explanation:

From the question awe are told that

                The distance between the two boats are 46 m

   Now we are told that a the time the Jenny's boat is at a crest,Melissa's boat is at its lowest point, and there are 4 additional crests between them which can be mathematically represented as

                         Number of wavelength = 4 + 0.5(this accounts for the difference in position crest and lowest point)

                                                              = 4.5

Now the wavelength of the water is \lambda = \frac{Distance }{Number \ of \ division }

                                                                 = \frac{46}{4.5} =10.22m

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Answer:

Part a)

f = \frac{8}{9}

Part b)

f = \frac{120}{169}

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So from above discussion we have the result that energy loss will be more if the collision occurs with animal with more mass

Explanation:

Part a)

Let say the collision between Moose and the car is elastic collision

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also by elastic collision condition we know that

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now we have

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Now loss in kinetic energy of the car is given as

\Delta K = \frac{1}{2}m(v_o^2 - v_{1f}^2)

\Delta K = \frac{1}{2}m(v_o^2 - \frac{v_o^2}{9})

so fractional loss in energy is given as

f = \frac{\Delta K}{K}

f = \frac{\frac{4}{9}mv_o^2}{\frac{1}{2}mv_o^2}

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Part b)

Let say the collision between Camel and the car is elastic collision

So here we can use momentum conservation

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so fractional loss in energy is given as

f = \frac{\Delta K}{K}

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Part c)

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