All categories

4 years ago

Which terms describe two atoms when they form a bond in which electrons are completely transferred from one atom to the other?

Physics

1 answer:

notka56 [123]4 years ago

4 0

Answer:

Ionic bonding

Explanation:

Ionic bonding:-

This type of bonding is formed when there is a complete transfer of electrons from one element to another element. In this bonding one element is always a metal and another is a non-metal.

For example, Calcium iodide

Calcium is the element of second group and forth period. The electronic configuration of Calcium is - 2, 8, 8, 2 or $1s^22s^22p^63s^23p^64s^2$

There are 2 valence electrons of Calcium.

Iodine is the element of seventeenth group and fifth period. The electronic configuration of Iodine is - 2, 8, 18, 18, 7 or $[Kr]4d^{10}5s^25p^5$

There are 7 valence electrons of iodine.

Calcium iodide, $CaI_2$ is formed when 2 valence electrons of calcium are loosed and they are gained by 2 atoms of iodine.

You might be interested in

An RC circuit consists of a resistor with resistance 1.0 kΩ, a 120-V battery, and two capacitors, C1 and C2, with capacitances o

Serhud [2]

Answer:

$Q_t= 8.3 * 10^3 C$

Explanation:

From the question we are told that:

Resistor $R=1000ohms$

Voltage $v=120_V$

Capacitance of c_1 $c_1=20 \mu F$

Capacitance of c_2 $c_2=60 \mu F$

Time $t=0$

Generally the equation for charges is mathematically given by

$For C_1\\Charge\ on\ C_1 = CV = 20*120 = 2400 μC = 2.4 x 10^-3 C\\Charge\ on\ C_1 = 2400 μC = 2.4 x 10^-3 C\\Charge\ on\ C_1 = 2.4 x 10^-3 C\\$

$ForC_2\\Charge on C_2 = 60*120 =7200 μC = 7.2 x 10^-3\\Charge on C_2 = 7.2 x 10^-3$

Generally the equation for voltage across capacitors is mathematically given by

$V_c(t)=V(1-e^{-t/RC})$

$C=C_1+C_2=80 \mu f\\t=2RC=>160000s$

$V_c(t)=120(1-e^{-(160000)/1000*(80)})$

$V_c(t)=103.7598$

Generally the equation for charges is mathematically given by

$Q1(t) = C1Vc(t)\\Q1(t) = 20*103.7598\\Q1(t) = 2075.196\\\\Q2(t) = 60*103.7598\\Q2(t) = 6225.6\\$

Generally the equation for total charges $Q_t$ is mathematically given by

$Q_t=Q1(t)+Q2(t)$

$Q_t= 8.3 * 10^3 C$

5 0

3 years ago

If an airplane is moving at a constant speed of 500 miles per hour in a straight line is it accelerating?

Zinaida [17]

No. It’s moving at a constant speed (speed is not changing) in a straight line (same direction so velocity is not changing) so it is not accelerating. Acceleration only occurs if there’s a change in speed/velocity.

4 0

4 years ago

Read 2 more answers

Can you get your sphere to ever be fully lit (lit on both halves)? If not, why?

BartSMP [9]

Answer:

Explanation:

think of the sphere like earth, light isnt on both sides during day. Its just like a sphere it wont be fully light.

7 0

3 years ago

Read 2 more answers

Suppose that a car traveling to the west (the - x direction) begins to slow down as it approaches a traffic light. Which stateme

Amanda [17]

Answer:

(A) it's acceleration is negative but but it's velocity is positive

Explanation:

In the question it is given that begins to slow down so its speed is decreasing it is does not means that its speed is negative

For example let first the velocity of the car is 30 m/sec and when its velocity decreases it becomes 20 m/sec in 5 sec

So it is not negative at all

Now the acceleration is the rate of change of velocity

$a=\frac{dv}{dt}$

$a=\frac{v_2-v_1}{dt}=\frac{20-30}{5}=-2 m/sec^2$

So acceleration is negative here

So option (a) will be the correct option

4 0

3 years ago

A 6.30 kg piece of solid copper metal at an initial temperature T is placed with 2.00 kg of ice that is initially at -16.0 ∘C. T

Viktor [21]

Answer:

179 degree

Explanation:

Solid copper will lose heat to warm up and melt ice . Since all the ice has not melted so final temperature of mixture will be zero.

heat gained by ice to reach temperature of zero degree

= mass of ice x specific heat of ice x rise of temp

= 2 x 2093 x 16 = 66976 J

Heat gained to melt 1.1. kg of ice

mass x latent heat of ice

1.1 x 334000

= 367400

total heat

= 367400 + 66976

=434376

Heat lost by copper

= 6.3 x 385 x T

where 385 is specific heat of copper and T is initial temperature

heat lost = heat gained

6.3 x 385 T = 434376

T = 434376 / (6.3 x 385)

= 179 degree .

3 0

3 years ago