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Svetllana [295]
3 years ago
14

Mary has 5370 $,she spent 2030$,what fraction of money did she spend

Mathematics
2 answers:
Artyom0805 [142]3 years ago
5 0
A fraction is the same as dividing something.

2030/5370

You can simplify by dividing (by 10)

203/537 is the fraction. Hope this helps, please mark as brainliest answer if it did! :)
Roman55 [17]3 years ago
3 0
5370 minus 2030 is 3340
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Plz help me i need this in simplest form or in a decimal
Snezhnost [94]

Answer:

1/1024 or .0009765625

Step-by-step explanation:

1/4 to the third power is 1/64

1/4 to the second power is 1/16

Then multiply 1/64 and 1/16 and get 1/1024 or .0009765625

Hope this helps dude

6 0
3 years ago
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20 points!
guapka [62]

C

Step-by-step explanation:

15/16-3/8 is equal to 0.5625. One half is 0.5 answer C is closest.

6 0
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Investment of $2000 at 10% simple interest for 9 years
Oliga [24]

Answer:

The last investment (C) has the least interest of $600

The other two investments (A and B) have the <u>same</u> amount of interest of $1800.

Step-by-step explanation:

<u>Simple Interest Formula</u>

I = Prt

where:

  • I = interest earned
  • P = principal
  • r = interest rate (in decimal form)
  • t = time (in years)

<u>Investment A</u>

  • P = $2000
  • r = 10% = 0.1
  • t = 9 years

Substitute the given values into the formula and solve for I:

⇒ I = 2000(0.1)(9)

⇒ I = $1800

<u>Investment B</u>

  • P = $3000
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Substitute the given values into the formula and solve for I:

⇒ I = 3000(0.03)(20)

⇒ I = $1800

<u>Investment C</u>

  • P = $2000
  • r = 10% = 0.1
  • t = 3 years

Substitute the given values into the formula and solve for I:

⇒ I = 2000(0.1)(3)

⇒ I = $600

The last investment (C) has the least interest of $600.

The other two investments (A and B) have the <u>same</u> amount of interest of $1800.

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Ilia_Sergeevich [38]
The product must be greater than 6, because. 1-3/4 is greater than ' 1 '. The product is "take 6 more than 1 time".
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Solve the inequality and graph its solution...<br> 2x+4≥24
Dima020 [189]
X=10
This is the answer to sol e for your equation you are asking

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