For a particular angle theta, the cosine function f(x) = a cos b(theta) has the following values within one cycle of the functio
n...:- f(0) = 2, f(pi/4) = 0, f(pi/2) = -2, f(3pi/4) = 0, f(pi) = 2
what is the rule for the cosine function???
2 answers:
Answer:
f(x) = 2 cos 2θ
Step-by-step explanation:
Equation is f(x) = a cos bθ
We have f(0) = 2
a cos (b x 0) = 2
a = 2
So f(x) = 2 cos bθ
We also have 

So the equation is f(x) = 2 cos 2θ
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