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3 years ago

10

Use the following information to find x. Write the value of the variable.

1 answer:

zhuklara [117]3 years ago

3 0

Step-by-step explanation:

can you elaborate on this problem a bit more? I just want to give you an accurate anwser

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Can you plz help me plz

Harman [31]

Answer:b=16

Step-by-step explanation:trust me bro

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3 years ago

Read 2 more answers

The scale factor to dilate Triangle ABC to Triangle DEF is _.

zaharov [31]

1/2

If ABC ~ DEF then 12/6, 16/8, and 18/9 would equal 2
BUT since we are going from a large triangle to a small triangle, our answer needs to be less then one, making our answer 1/2

3 0

3 years ago

X^2+5x=3x+11 solve by completing the square

goldenfox [79]

X^2+2x-11=0, this would be the answer that you are looking for m8.

7 0

3 years ago

Need help with Calculus 1 inverse trig functions

lidiya [134]

Answer:

$\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{2+2x^2+2x\sqrt{1+x^2}}$

Step-by-step explanation:

<u>The Derivative of a Function</u>

The derivative of f, also known as the instantaneous rate of change, or the slope of the tangent line to the graph of f, can be computed by the definition formula

$\displaystyle f'(x)=\lim\limits_{\Delta x \rightarrow 0}\frac{f(x+\Delta x)-f(x)}{\Delta x}$

There are tables where the derivative of all known functions are provided for an easy calculation of specific functions.

The derivative of the inverse tangent is given as

$\displaystyle (tan^{-1}u)'=\frac{u'}{1+u^2}$

Where u is a function of x as provided:

$y=3tan^{-1}(x+\sqrt{1+x^2})$

If we set

$u=(x+\sqrt{1+x^2})$

Then

$\displaystyle u'=1+\frac{2x}{2\sqrt{1+x^2}}$

$\displaystyle u'=1+\frac{x}{\sqrt{1+x^2}}$

Taking the derivative of y

$y'=3[tan^{-1}(x+\sqrt{1+x^2})]'$

Using the change of variables

$\displaystyle y'=3[tan^{-1}u]'=3\frac{u'}{1+u^2}$

$\displaystyle y'=3\frac{u'}{1+u^2}=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{1+(x+\sqrt{1+x^2})^2}$

Operating

$\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{1+x^2+2x\sqrt{1+x^2}+1+x^2}$

$\boxed{\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{2+2x^2+2x\sqrt{1+x^2}}}$

8 0

3 years ago

A baseball team has won 8 out of the first 20 games and has 40 games remaining. The team needs a winning percentage of 62.5% mak

dimaraw [331]

Answer:

30 More Games for Playoffs | Win Percentage of 40% in Playoffs

Step-by-step explanation:

We find the total amount of games by adding first 20 and 40 remaining

This will leave us with 60 games

In order to calculate the playoff, we would have to calculate 62.50% in those 60 games.

62.50% is 5/8, we divide 60 by 8 and get 7.50

We multiply both sides by 7.50 and get 37.50/60

We subtract 8 from 37.50 and get 29.50

We round it to the nearest ones and get 30

In order to win the game they would need to win 30 more games

To calculate the final win percentage, we would add 2 and 3, which would give us 5.

After winning 2 and losing 3,

it would give us 2/5,

which in percentage is 40%

8 0

3 years ago