Answer: 109.1 degrees
Step-by-step explanation:
To find the angle between the given vectors, we will use the formula below:
Cos(θ) = (U.V)/ |U|.|V|
Where
U = 13i - 8j
V = 2i + 9j
U.V = (2x13) + (-8×9)
U.V = 26 - 72
U.V = - 46
|U| = sqrt ( 13^2 + 8^2)
= sqrt ( 233) = 15.264
|V| = sqrt( 2^2 + 9^2)
= sqrt ( 85 ) = 9.22
Substitute all the value of the parameters into the formula
Cos ø = -46 / (15.3 × 9.2)
Cos ø = - 46 / 140.72
Cos Ø = - 32687
Find the cos inverse of the value
Ø = cos^-1( -32687)
Ø = 109.079 degrees
Therefore, the angle between the given vectors to the nearest tenth of a degree is 109.1 degrees
Hello!
To solve this problem, we will use a system of equations. We will have one number be x and the other y. We will use substitutions to solve for each variable.
x+y=9
x=2y-9
To solve for the two numbers, we need to solve the top equation. The second equation shows that x=2y-9. In the first equation, we can replace 2y-9 for x and solve.
2y-9+y=9
3y-9=9
3y=18
y=6
We now know the value of y. Now we need to find x. We can plug in 6 for y in the second equation to find x.
x=2·6-9
x=12-9
x=3
Just to check, we will plug these two numbers into the first equation.
3+6=9
9=9
Our two numbers are three and six.
I hope this helps!
