-4(-x-10)= 4x• 40
11g+4-6g+7s-10 =16g+6-7s
3(10+9x)+11-3x= 13x+19
Answer:
zeros -1,3 and the factors ( x+1) (x-3)
Step-by-step explanation:
The zeros are where it crosses the x axis
It crosses at x=-1 and x=3
So the factors are ( x- -1) and ( x-3)
( x+1) (x-3)
(6.2) and the perpendicularly to y = to 1223
It will land on its side 24/60. If we simplify this we get 2/5
Given:
The function, f(x) = -2x^2 + x + 5
Quadratic equation: 0 = -2x^2 + x +5
where a = -2
b = 1
c = 5
The discriminate b^2 - 4ac = 41
To solve for the zeros of the quadratic function, use this formula:
x = ( -b +-√ (b^2 - 4ac) ) / 2a
x = ( 1 + √41 ) / 4 or 1.85
x = ( 1 - √41 ) / 4 or -1.35
Therefore, the zeros of the quadratic equation are 1.85 and -1.35.
