B) y = -2x
when x = a
y = -2a
when x= 2a
y = -2(2a) = -4a
-- The square of the shortest side . . . 16² = 256
-- The square of the medium side . . . 30² = 900
-- Their sum . . . (256 + 900) = <u>1,156</u>
-- The square of the longest side = 35² = <u>1,225</u>
1,156 and 1,225 are not equal, so these 3 numbers
<em>can</em> be the sides of a triangle, but it's not a right one.
The statement is <em>false</em>. (choice 'b')
The result of our calculations about the rate and time are:
<h3>What is rate?</h3>
Rate can be regarded as the given object with respect to time.
falcon flies= 800,000 meters
t= 4 hours
We were given the formula as (d = rt)
d= distance
r = rate
t = time
We can make our calculations as:
part a:
r=d/t
part b:
falcon's rate in meters per hour = 800,000 meters / 4 hours = 200000m/hr
part c:
falcon's rate in kilometers per hour=(200000m/hr *(1/1000)=200km/hr
part d:
km/hr
Learn more about rate at:
brainly.com/question/8728504
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The requirement is that every element in the domain must be connected to one - and one only - element in the codomain.
A classic visualization consists of two sets, filled with dots. Each dot in the domain must be the start of an arrow, pointing to a dot in the codomain.
So, the two things can't can't happen is that you don't have any arrow starting from a point in the domain, i.e. the function is not defined for that element, or that multiple arrows start from the same points.
But as long as an arrow start from each element in the domain, you have a function. It may happen that two different arrow point to the same element in the codomain - that's ok, the relation is still a function, but it's not injective; or it can happen that some points in the codomain aren't pointed by any arrow - you still have a function, except it's not surjective.
