All categories

3 years ago

What is the slope of a line that is perpendicular to the line whose equation is y= 4x – 3?

Mathematics

2 answers:

Ira Lisetskai [31]3 years ago

7 0

Answer:

-1/ 4

Step-by-step explanation:

y = 4x-3 has a slope of 4 because the equation is in slope intercept form

y = mx+b where the slope is m

Perpendicular lines have slopes that are negative reciprocals

-1/ 4 is the slope of a line that is perpendicular to y = 4x-3

shepuryov [24]3 years ago

7 0

Answer:

Antes de empezar a resolver el problema primero te digo adios

Step-by-step explanation:

Y muchas gracias por los puntos

You might be interested in

What is the area, in square units, of triangle $ABC$ in the figure shown if points $A$, $B$, $C$ and $D$ are coplanar, angle $D$

Zolol [24]

Answer:

The answer is 24.

6 0

3 years ago

What is the factorization??

aivan3 [116]

We first find the zeros of the function , the zeros of the function are those at which points the graph of the function crosses or touches the x axis

here we can see in the graph that graph crosses the x axis at two points , 1 and 7

So the zeros of the function are

x=1 and x=7

It means the factor are

(x-1) and (x-7)

So the factorization is given by

(x-1)(x-7)

7 0

3 years ago

What is the lcm of 150 and 180

xxTIMURxx [149]

Answer:

900

Step-by-step explanation:

multiply 2x2x3x3x5x5

4x9x25 which is 900

8 0

3 years ago

What is the value of x?<br> Please help fast will give brainliest help fast

serious [3.7K]

Answer:

Step-by-step explanation:

because of the kind of angle it is, the two equations are equal. So, put the equations equal to each other and solve:

x+35=3x+1

combine like terms (by subtracting)

2x=34

isolate x by dividing by 2

x=17

8 0

3 years ago

Read 2 more answers

What is the simplified form of StartRoot StartFraction 72 x Superscript 16 Baseline Over 50 x Superscript 36 Baseline EndFractio

aalyn [17]

Answer:

StartFraction 6 Over 5 x Superscript 10 Baseline EndFraction

Step-by-step explanation:

Apparently you want to simplify ...

$\sqrt{\dfrac{72x^{16}}{50x^{36}}}$

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

1/a^b = a^-b

(a^b)^c = a^(bc)

So the expression simplifies as ...

$\sqrt{\dfrac{72x^{16}}{50x^{36}}}=\sqrt{\dfrac{36}{25x^{36-16}}}=\sqrt{\dfrac{36}{25x^{20}}}\\\\\sqrt{\left(\dfrac{6}{5x^{10}}\right)^2}=\boxed{\dfrac{6}{5x^{10}}}$

9 0

3 years ago