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Serggg [28]
3 years ago
11

What is 8/12 and 7/8 close to 0, 1, 1/2

Mathematics
1 answer:
Genrish500 [490]3 years ago
8 0
It is closer to 1 hope i helped

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matthew scored a total of 168 points in basketball this season. He scored 147 of those points what perenct of his total points d
natka813 [3]
88% not sure but I think so if it’s not the answer I’m sorry.
7 0
3 years ago
A line passes through the points (-2, 9) and (1, 3).
siniylev [52]

Answer:

slope = -2

y-intercept = 5

Step-by-step explanation:

1) Find slope:

\frac{3-9}{1-(-2)} =  \frac{-6}{3} = -2

-2 = slope

2) Find y intercept trough point slope and slope-intercept forms

y - y1 = m (x - x1)

y - 9 = -2 (x + 2)

y - 9 = -2x -4

  + 9         + 9

y = -2x + 5

y = mx + b with b being the y-intercept

5 = y-intercept

7 0
2 years ago
Determine the location and values of the absolute maximum and absolute minimum for given function : f(x)=(‐x+2)4,where 0<×&lt
brilliants [131]

Answer:

Where 0 < x < 3

The location of the local minimum, is (2, 0)

The location of the local maximum is at (0, 16)

Step-by-step explanation:

The given function is f(x) = (x + 2)⁴

The range of the minimum = 0 < x < 3

At a local minimum/maximum values, we have;

f'(x) = \dfrac{(-x + 2)^4}{dx}  = -4 \cdot (-x + 2)^3 = 0

∴ (-x + 2)³ = 0

x = 2

f''(x) = \dfrac{ -4 \cdot (-x + 2)^3}{dx}  = -12 \cdot (-x + 2)^2

When x = 2, f''(2) = -12×(-2 + 2)² = 0 which gives a local minimum at x = 2

We have, f(2) = (-2 + 2)⁴ = 0

The location of the local minimum, is (2, 0)

Given that the minimum of the function is at x = 2, and the function is (-x + 2)⁴, the absolute local maximum will be at the maximum value of (-x + 2) for 0 < x < 3

When x = 0, -x + 2 = 0 + 2 = 2

Similarly, we have;

-x + 2 = 1, when x = 1

-x + 2 = 0, when x = 2

-x + 2 = -1, when x = 3

Therefore, the maximum value of -x + 2, is at x = 0 and the maximum value of the function where 0 < x < 3, is (0 + 2)⁴ = 16

The location of the local maximum is at (0, 16).

5 0
3 years ago
Which equation is equivalent to √x^2+81 = x+10
jeka57 [31]

Keywords:

<em>equation, operations, equivalent, binomial, square root </em>

For this case we have an equation in which we must apply operations to rewrite it in an equivalent way. We must start by raising both sides of the equation to the square. Thus, we eliminate the square root of the left side of equality and finally solve the binomial of the right side of equality.

So we have:

\sqrt {x ^ 2 + 81} = x + 10\\(\sqrt {x ^ 2 + 81}) ^ 2 = (x + 10) ^ 2\\x ^ 2 + 81 = (x + 10) ^ 2

By definition:(a + b) ^ 2 = a ^ 2 + 2ab + b ^ 2

x ^ 2 + 81 = x ^ 2 + 2 (x) (10) + (10) ^ 2\\x ^ 2 + 81 = x ^ 2 + 20x +100

Thus, x ^ 2 + 81 = x ^ 2 + 20x +100 is equivalent to \sqrt {x ^ 2 + 81} = x + 10

Answer:

x ^ 2 + 81 = x ^ 2 + 20x +100

Option D

4 0
3 years ago
Read 2 more answers
Express the radical using the imaginary unit, i.
MrMuchimi

Answer:

±3i

Step-by-step explanation:

Given the value ±√-9, we are to express the value using the imaginary number 'I'

±√-9 = ±√9×-1

= ±√9 × √-1

In complex number, √-1 = i

The expression becomes;

±√9 = ±3 × i

±√9 = ±3i

Hence the value in simplified form is ±3i

7 0
3 years ago
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