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3 years ago

Jack has a Rock. The Rock has a mass of 6g and a volume of 3ml. what is the density of The Rock?

Mathematics

1 answer:

Vlada [557]3 years ago

7 0

Step-by-step explanation:

Density = Mass ÷ Volume

= 6 ÷ 3

= 2g/cm³

Answer : 2g/cm³

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For a trip Eli packed 4 shirts, 2 pairs of pants, and 2 pairs of shoes. How many different outfits can Eli make?

Lorico [155]

4 shirts can be worn with one pair of pants twice and the shoes can be paired with each outfit. So I am going to say 8 outfits.

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3 years ago

15 points PLEASE HELP!!!<br><br> Factor the following equation:<br> <img src="https://tex.z-dn.net/?f=x%5E2%2B3x%2B4" id="TexFor

ycow [4]

Step-by-step explanation:

x²+3x+4=0

x²+3x_ +2=0

x²+3x_2=-2

x²+3x_2+(3x_4)²=-2+(3/4)²

(x+3/4) =-2+9_16

x+3_4 = -32+9__16 =√-23_6

x+3_4 =-√23_4

x = -3+√-23___4

x = -3- √-23___4 , -3+√-23___4 //

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5 0

2 years ago

Can someone please write the points in a notebook please I really need help

nordsb [41]

Answer:

Step-by-step explanation:

8 0

3 years ago

The length of FH is 9 cm. What is the length of GK? SHOW STEPS AWARDING BRAINLY

DanielleElmas [232]

Answer:

GK = 9cm

Step-by-step explanation:

Length of diagonal FH = 9 cm

By the property of a rectangle,

"Lengths of the diagonals of a rectangle measure the same"

FH = GK

Therefore, GK = FH = 9cm

7 0

3 years ago

If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle? A) (x

Andrei [34K]

Answer:

$\large\boxed{A.\ (x+6)^2+(y+10)^2=20}$

Step-by-step explanation:

The standard form of an equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the endpoints of the diameter of a circle (-8, -6) and (-4, -14).

The midpoint of a diameter is a center of a circle.

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$x=\dfrac{-8+(-4)}{2}=\dfrac{-12}{2}=-6\\\\y=\dfrac{-6+(-14)}{2}=\dfrac{-20}{2}=-10$

We have h = -6 and k = -10.

The radius is the distance between a center and the point on a circumference of a circle.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute (-6, -10) and (-8, -6):

$r=\sqrt{(-8-(-6))^2+(-6-(-10))^2}=\sqrt{(-2)^2+4^2}=\sqrt{4+16}=\sqrt{20}$

Finally we have

$(x-(-6))^2+(y-(-10))^2=(\sqrt{20})^2\\\\(x+6)^2+(y+10)^2=20$

5 0

3 years ago

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