3
8(3)(1/2)=12
2(1/2)(4)=4
12/4=3
Using properties of the logarithm, you can rearrange the integrand as

Then recall that the integral of
is

(or you can find that out by integrating by parts) and so

Answer:
2π/3, 4π/3
Step-by-step explanation:
I interpret your question as asking us to solve the equation
2cos(x) + 1 = 0
2cos(x) = -1
cos(x) = -½x
x = arccos(-½), 0 ≤ x ≤2π
Since the cosine is negative, x must be in the second or third quadrant.
Referring to the unit circle, we find that
x = 2π/3 (120°) or x = 4π/3 (240°)
Answer:
the answer is -1 its 1 Because you divide
Answer:
in the first box put k-15=33
in the second box put k=48
Step-by-step explanation:
if you look at what it says, it says 33 is 15 less than k. so we know that we are going to have 33 on one side and k and 15 on the other. it also says 15 less than k, so that would be k-15
33=k-15 or k-15=33
now we have to solve this. add 15 to each side to cancel out the -15
that gives you k=48