D(7, 3), E(8, 1), and F(4, -1)
We calculate the squared distances between the points:
Since 
we have a right triangle with hypotenuse DF.
From the Special Triangle Theorem, the hypotenuse is equal to the side lengtht times the Sqrt(2).
So hypotenuse H = xSqrt(2), x=H/Sqrt(2).
Using numbers, if H = 7, then x = 7/Sqrt(2) = 7Sqrt(2)/2 to rationalize it.
To solve this, set up two equations using the information you're given. Let's call our two numbers a and b:
1) D<span>ifference of two numbers is 90
a - b (difference of two numbers) = 90
2) The quotient of these two numbers is 10
a/b (quotient of the two numbers) = 10
Now you can solve for the two numbers.
1) Solve the second equation for one of the variables. Let's solve for a:
a/b = 10
a = 10b
2) Plug a =10b into the first equation and solve for the value of b:
a - b = 90
10b - b = 90
9b = 90
b = 10
3) Using b = 10, plug it back into one of the equations to find the value of a. I'll plug it back into the first equation:
a - b = 90
a - 10 = 90
a = 100
-------
Answer: The numbers are 100 and 10</span>
Hi there!
0.66 ÷ 15.18 = 0.04347826
0.66 ÷ 15.18 ≅0.04
There you go! I really hope this helped, if there's anything just let me know! :)
9514 1404 393
Answer:
63
Step-by-step explanation:
Reversing the digits changes the value by a factor of 9 times the difference in the digit values. Here, this means the digits differ by 27/9 = 3. If one digit is double the other, the higher digit is 2×3 = 6.
The number is 63.
_____
If you like, you can work through the algebra of it. Let the original number have tens digit x and ones digit y.
original number value = 10x +y
reversed number value = 10y +x
difference of values = 27 = (10x +y) -(10y +x) = 9(x -y)
The tens digit is twice the ones digit, so we have ...
x = 2y
Substituting in the difference equation, we have ...
27 = 9(x -y)
3 = (2y -y) = y . . . . . divide by 9, substitute for x
x = 2(3) = 6
The number is 10x+y = 63.
