Step-by-step explanation: need to find a basis for the solutions to the equation Ax = 0. To do this ... 0 0 0 1 −3. ⎤. ⎦. From this we can read the general solution, x = ⎡. ⎢. ⎢. ⎢. ⎢. ⎣ ... two vectors are clearly not multiples of one another, they also give a basis. So a basis ... 4.4.14 The set B = {1 − t2,t − t2,2 − 2t + t2} is a basis for P2.
Answer:
Im pretty sure ur answers would be
x= -32/27 and X= -46/27
Step-by-step explanation:
So srry if im wrong tho
Answer: I took it last year as a junior, what is the questions tho?
A. 2(-2) - 3
-4 - 3
-7
b. 2(7) - 3
14 - 3
11
2(-4) - 3
-8 - 3
- 11
