Answer:
angle Q = 66
Step-by-step explanation:
nvm ik how to do it
First find the value of u
2u + 6 + 3u + 24 = 180 degrees
combine like terms
5u + 30 = 180 degrees
subtract 30 from each side
5u = 150
divide each side by 5
u = 30
plug it in
2(30) + 6
60 + 6 = 66
angle Q = 66
Answer:
(2, - 5)
Explanation:
The line y = -1 is horizontal: parallel to the y-axis.
The point B (2,3) is above the line y = - 1 at a distance equal to the y-coordinate of B (y = 3) less - 1:
Δy = 3 - ( - 1) = 4
When the point B (2,3) is reflected over the line y = -1, the x-coordinate does not change. The image will be 4 units down the line y = -1, thus the y-coordinate will be - 1 - 4 = - 5.
Hence, the coordinates of the vertex B' are x = 2, y = - 5: (2, - 5).
Answer:
B
Step-by-step explanation:
![\boxed{area \: of \: sector = \frac{1}{2} {r}^{2} θ }](https://tex.z-dn.net/?f=%5Cboxed%7Barea%20%5C%3A%20of%20%5C%3A%20sector%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%7Br%7D%5E%7B2%7D%20%CE%B8%20%7D)
Radius= diameter ÷2
r= 32 ÷2
r= 16
![\frac{1}{2} {r}^{2} θ = \frac{512\pi}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20%20%7Br%7D%5E%7B2%7D%20%CE%B8%20%3D%20%20%5Cfrac%7B512%5Cpi%7D%7B3%7D%20)
Substitute r= 16,
![\frac{1}{2} ( {16}^{2} )(θ) = \frac{512\pi}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20%28%20%7B16%7D%5E%7B2%7D%20%29%28%CE%B8%29%20%3D%20%20%5Cfrac%7B512%5Cpi%7D%7B3%7D%20)
![128 \: θ = \frac{512\pi}{3} \\ θ = \frac{512\pi}{3} \div 128 \\ θ = \frac{512\pi}{384}](https://tex.z-dn.net/?f=128%20%5C%3A%20%CE%B8%20%3D%20%20%5Cfrac%7B512%5Cpi%7D%7B3%7D%20%20%5C%5C%20%CE%B8%20%3D%20%20%5Cfrac%7B512%5Cpi%7D%7B3%7D%20%20%5Cdiv%20128%20%5C%5C%20%CE%B8%20%3D%20%20%5Cfrac%7B512%5Cpi%7D%7B384%7D%20)
Divide the denominator and numerator by 128:
![θ = \frac{4\pi}{3}](https://tex.z-dn.net/?f=%CE%B8%20%3D%20%20%5Cfrac%7B4%5Cpi%7D%7B3%7D%20)
Thus, the answer is B.
6500 is the correct answer