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Brilliant_brown [7]
3 years ago
7

Please help me please plase plase plase

Mathematics
2 answers:
Marianna [84]3 years ago
7 0
Equation: (20•13)3+(12•10/2)2
answer: 900 ft sq
marysya [2.9K]3 years ago
4 0

Answer:

840 square feet

Step-by-step explanation:

13 x 20 = 260 x 2 = 520

10 x 12 / 2 = 60 x 2 = 120

10 x 20 = 200

520 + 120 + 200 = 840

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What is 6912 cube root
nataly862011 [7]

Answer:

19.048

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
1. A luge race is very dangerous, and a crash can cause serious injuries. The league requires anyone who has a crash to have a t
antiseptic1488 [7]

Answer:

0.7061 = 70.61% probability she will have her first crash within the first 30 races she runs this season

Step-by-step explanation:

For each race, there are only two possible outcomes. Either the person has a crash, or the person does not. The probability of having a crash during a race is independent of whether there was a crash in any other race. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A certain performer has an independent .04 probability of a crash in each race.

This means that p = 0.04

a) What is the probability she will have her first crash within the first 30 races she runs this season

This is:

P(X \geq 1) = 1 - P(X = 0)

When n = 30

We have that:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{30,0}.(0.04)^{0}.(0.96)^{30} = 0.2939

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.2939 = 0.7061

0.7061 = 70.61% probability she will have her first crash within the first 30 races she runs this season

7 0
3 years ago
Justin is on a road trip. Over the past two days, he’s driven a total distance of 504 miles at an average speed of 56 miles/hour
irakobra [83]
Recall d  = rt, distance = rate * time.

now, he has a speed rate of 56 mph for a distance of 504

\bf d=rt\implies 504=56t\implies \cfrac{504}{56}=t\implies \stackrel{hours}{9}=t

so, at that speed the whole driving time is 9 hours then.  Ok, he drove 2 hours today, that means he drove 7 yesterday, 9 - 2.

how many miles is it for 7 hours at 56mph?  d = rt ---> d = 56 * 7

that many miles he drove yesterday.
8 0
3 years ago
A boat travels 30 miles up the river in the same amount of time it takes to travel 38 miles down the same river. If the current
Ksenya-84 [330]
X miles per hour  -  <span> speed of the boat in still water
(x - 2)  -  speed up the river
(x + 2)  -  speed down the river
</span>
\frac{30}{x - 2} = \frac{38}{x + 2}
30 * (x + 2) = 38 * (x - 2)
30x + 60 = 38x - 76
- 8x = - 136
x = 17 miles per hour  -  <span>the speed of the boat in still water.</span>
5 0
3 years ago
Mary throws her Grandma’s favorite crystal dish out the second floor window, which is 6 meters from the ground. She is really up
wlad13 [49]

we know that

acceleration due to gravity is 9.8m/s^2

so, we get

a(t)=9.8

and acceleration will always be constant

we know that

integral of acceleration is velocity

so, we can integrate both sides

\int \:a\left(t\right)dt=\int \:9.8dt

v(t)=9.8t+C

we are given

v(0)=35m/s

we can use it and find C

v(0)=9.8*0+C

35=9.8*0+C

C=35

now, we can plug it back

v(t)=9.8t+35

we know that

integral of velocity is height

we can integrate it again

\int \:v\left(t\right)dt=\int \:\left(9.8t+35\right)dt

s(t)=\int \:\left(9.8t+35\right)dt

s(t)=4.9t^2+35t+C

now, we have

s(0)=6

we can use it and find C

s(0)=4.9(0)^2+35(0)+C

6=4.9(0)^2+35(0)+C

now, we can plug back C

C=6

and we get

s(t)=4.9t^2+35t+6.............Answer

4 0
4 years ago
Read 2 more answers
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