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Aleks04 [339]
3 years ago
15

" \frac{1}{8} + \frac{1}{3} = " alt=" \frac{1}{8} + \frac{1}{3} = " align="absmiddle" class="latex-formula">

Mathematics
1 answer:
barxatty [35]3 years ago
6 0

Answer:

It won't do you any good to just copy the answer. You need to know that, for example,

\frac{13}{17}=\frac{13}{17}\times\frac{123457}{123457}=\frac{13\times123457}{17\times123457}=\frac{1604941}{2098769}

The 3 numbers (13,17,123457) are just examples; the equation is true for all such numbers except zero.

Once you know that, you need to know how to add fractions with the same denominator:

\frac{2}{23}+\frac{3}{23}=\frac{5}{23}

Next, you have to know that you can't add fractions with different denominators.

Instead, you have to use the first trick to change the fractions so they have the same denominators without changing the value of either fraction.

\frac{1}{3}+\frac{1}{8}=\frac{1}{3}\times\frac{8}{8}+\frac{1}{8}\times\frac{3}{3}=\frac{1\times8}{3\times8}+\frac{1\times3}{8\times3}=\frac{8+3}{3\times8}

Once you know how to do this, you can add fractions, but you might end up with results that are like

\frac{1604941}{2098769}\text{ which is really just }\frac{13}{17}

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The response to a question has three alternatives: A, B, and C. A sample of 120 responses provides 60 A, 12 B, and 48 C. Show th
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Answer:

CLASS     FREQUENCIES     RELATIVE FREQUENCIES

A                        60                                 0.5

B                        12                                  0.1

C                        48                                 0.4

TOTAL              120                                  1

Step-by-step explanation:

Given that;

the frequencies of there alternatives are;

Frequency A = 60

Frequency B = 12

Frequency C = 48

Total = 60 + 12 + 48 = 120

Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;

Relative Frequency A = Frequency A / total = 60 / 120 = 0.5

Relative Frequency B = Frequency B / total = 12 / 120 = 0.1

Relative Frequency C = Frequency C / total = 48 / 120 = 0.4

therefore;

CLASS     FREQUENCIES     RELATIVE FREQUENCIES

A                        60                                 0.5

B                        12                                  0.1

C                        48                                 0.4

TOTAL              120                                  1

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