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Aleks04 [339]
3 years ago
15

" \frac{1}{8} + \frac{1}{3} = " alt=" \frac{1}{8} + \frac{1}{3} = " align="absmiddle" class="latex-formula">

Mathematics
1 answer:
barxatty [35]3 years ago
6 0

Answer:

It won't do you any good to just copy the answer. You need to know that, for example,

\frac{13}{17}=\frac{13}{17}\times\frac{123457}{123457}=\frac{13\times123457}{17\times123457}=\frac{1604941}{2098769}

The 3 numbers (13,17,123457) are just examples; the equation is true for all such numbers except zero.

Once you know that, you need to know how to add fractions with the same denominator:

\frac{2}{23}+\frac{3}{23}=\frac{5}{23}

Next, you have to know that you can't add fractions with different denominators.

Instead, you have to use the first trick to change the fractions so they have the same denominators without changing the value of either fraction.

\frac{1}{3}+\frac{1}{8}=\frac{1}{3}\times\frac{8}{8}+\frac{1}{8}\times\frac{3}{3}=\frac{1\times8}{3\times8}+\frac{1\times3}{8\times3}=\frac{8+3}{3\times8}

Once you know how to do this, you can add fractions, but you might end up with results that are like

\frac{1604941}{2098769}\text{ which is really just }\frac{13}{17}

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Determine whether the given sequence could be geometric, arithmetic, or neither. if possible, identify either the common ratio o
REY [17]

ARITHMETIC CHECK: A sequence is said to be arithmetic if any two consecutive terms differ by the same constant.

So, the test to check if a series is arithmetic is to compute consecutive differences, and see if they all return the same number.

If we subtract the first two terms, we have 2-4 = -2. If we subtract the third and second terms, we have 1-2 = -1.

These two differences returned two different values, so the series is not arithmetic.

GEOMETRIC CHECK: A sequence is said to be geometric if any two consecutive terms are in the same ratio.

So, the test to check if a series is geometric is to compute consecutive ratios, and see if they all return the same number.

If we divide the first two terms, we have

\dfrac{2}{4} = \dfrac{1}{2}

If we divide the third and second terms, we have

\dfrac{1}{2} = \dfrac{1}{2}

Finally, if we divide the last two terms we have

\dfrac{\frac{1}{2}}{1} = \dfrac{1}{2}

So, all ratios return the same number. This means that the series is geometric, and the common ratio is 1/2



7 0
4 years ago
Given:<br> Set A = 1,6,9<br> Set B= 7, 9, 12<br> What is the union of sets A and B?
dmitriy555 [2]

Step-by-step explanation:

Union = elements of A + elements of B

Union = ( 1,6,7,9,12)

4 0
3 years ago
SOS HURRY
Burka [1]

First, by using the distance formula for just one side, we can find the length of all sides (a square has 4 equal sides.) Then, we can apply the area of a square formula, which is a^2.

Distance formula:

\sqrt{(x.2 - x.1)^{2} + (y.2 - y.1)^{2}}

√((-2 + 5)^2 + (-8 + 4)^2)

√((3)^2 + (4)^2)

√9 + 16

√25

5

The side lengths of the square are each equal to 5, and by applying the formula for area, we can find the area of the square.

5^2 = 25

<h3>The area is 25.</h3>
3 0
3 years ago
The mathematical expression 9€ T means
Kaylis [27]

Answer:

Given mathematical expression means that '9 is a member of the set T'.

Step-by-step explanation:

We are given the mathematical expression,

' 9 € T '.

In words, it means '9 belongs to T'.

That is, 'the element 9 belongs to the set T' i.e. '9 is a member of the set T'.

Hence, the given mathematical expression means that '9 is a member of the set T'.

7 0
3 years ago
Use a two-column proof to prove the Triangle Proportionality Theorem:
photoshop1234 [79]

Answer:

Step-by-step explanation:

From the picture attached,

                 Statements                                        Reasons

1). In ΔABC, DE intersects AB and AC  1). Given

2). DE║BC                                              2). Given

3). ∠ADE ≅ ABC                                    3). Corresponding angles postulate

4). ∠AED ≅ ∠ACB                                 4). Corresponding angles postulate

5). ΔADE ~ ΔABC                                  5). AA similarity postulate

6). \frac{AD}{AB}=\frac{AE}{AC}                                           6). Definition of two similar triangles

Hence proved.  

4 0
3 years ago
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