Ask question

Ask question

All categories

3 years ago

11

Jackson buys a grape snow cone on a hot day. By the time he eats all the "snow" off the top, the paper cone is filled with 27\pi

27π27, pi cm^3
3

cubed of melted purple liquid. The radius of the cone is 333 cm.

1 answer:

anyanavicka [17]3 years ago

4 0

Question:

Jackson buys a grape snow cone on a hot day. By the time he eats all the "snow" off the top, the paper cone is filled with 27\pi27π27, pi cm^3 3 start superscript, 3, end superscript of melted purple liquid. The radius of the cone is 333 cm. What is the height of the cone?

Answer:

The height of the cone is $9 \ cm$

Explanation:

It is given that the radius of the cone is $3 \ cm$

The volume of the cone is $27\pi$

The height of the cone can be determine using the formula,

$V=\frac{1}{3} \pi r^{2} h$

Substituting the values $V=27 \pi$ and $r=3$ , we get,

$27 \pi=\frac{1}{3} \pi(3)^{2} h$

Multiplying both sides by 3, we have,

$81 \pi= 9\pi h$

Dividing both sides by $9 \pi$ , we have,

$9=h$

Thus, the height of the cone is $9 \ cm$

You might be interested in

a cylinder with base are 169π ft^2 and a height twice the radius. what is the lateral area and surface area of the cylinder

Morgarella [4.7K]

$Area\ of\ base:A_B=169\pi\ ft^2\\\\A_B=\pi r^2\ \ \ (r-radius)\\\\\pi r^2=169\pi\ \ \ /:\pi\\\\r^2=169\\\\r=\sqrt{169}\\\\r=13\ (ft)\\\\H=2r\to H=2\cdot13=26\ (ft)$

$
lateral\ area:A_L=2\pi rH\\\\A_L=2\pi\cdot13\cdot26=676\pi\ (ft^2)\\\\Surface\ area:A_S=2A_B+A_L\\\\A_S=2\cdot169\pi+676\pi=338\pi+676\pi=1014\pi\ (ft^2)$

5 0

3 years ago

Read 2 more answers

Compare the values of each 3 in the number 633,248

ipn [44]

633,248.
The difference of each 3 is that they have different place values.
The 3 on the right side is int he 1000s (thousands) place, and the 3 on the left is in the 10,000s (ten thousands) place. :)

The one in the 10,000s place is 10 times larger than the one in the 1,000s place!

6 0

3 years ago

Edmond buys 4/5 of a kilogram of butterscotch chips and 5 kilograms of milk chocolate chips.

Vika [28.1K]

He spent $5.80.

1 x 4/5 = 0.8
1 x 5 = 5

8 0

2 years ago

I will mark you brainiest if you can answer this

Vika [28.1K]

Answer:

D

Step-by-step explanation:

7 0

3 years ago

The top and bottom margins of a poster are each 12 cm and the side margins are each 8 cm. The area of printed material on the po

grin007 [14]

Answer:

Dimensions of printed poster are

length is 32 cm

width is 48 cm

Step-by-step explanation:

Let's assume

length of printed poster is x cm

width of printed poster is y cm

now, we can find area of printed poster

so, area of printed poster is

$=xy$

we are given that area as 1536

so, we can set it to 1536

$xy=1536$

now, we can solve for y

$y=\frac{1536}{x}$

now, we are given

The top and bottom margins of a poster are each 12 cm and the side margins are each 8 cm

so, total area of poster is

$A=(8+x+8)\times (12+y+12)$

$A=(x+16)\times (y+24)$

now, we can plug back y

$A=(x+16)\times (\frac{1536}{x}+24)$

now, we have to minimize A

so, we will find derivative

$A'=\frac{d}{dx}\left(\left(x+16\right)\left(\frac{1536}{x}+24\right)\right)$

we can use product rule

$A'=\frac{d}{dx}\left(x+16\right)\left(\frac{1536}{x}+24\right)+\frac{d}{dx}\left(\frac{1536}{x}+24\right)\left(x+16\right)$

$=\frac{d}{dx}\left(x+16\right)\left(\frac{1536}{x}+24\right)+\frac{d}{dx}\left(\frac{1536}{x}+24\right)\left(x+16\right)$

now, we can simplify it

$A'=-\frac{24576}{x^2}+24$

now, we can set it to 0

and then we can solve for x

$A'=-\frac{24576}{x^2}+24=0$

$-\frac{24576}{x^2}x^2+24x^2=0\cdot \:x^2$

$-24576+24x^2=0$

$x=32,\:x=-32$

Since, x is dimension

and dimension can never be negative

so, we will only consider positive value

$x=32$

now, we can solve for y

$y=\frac{1536}{32}$

$y=48$

so, dimensions of printed poster are

length is 32 cm

width is 48 cm

5 0

3 years ago