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3 years ago

How does finding the square root of a number compare to finding the cube root of a number?

Mathematics

1 answer:

Setler79 [48]3 years ago

8 0

Answer:

See explanation below

Step-by-step explanation:

To find the principal square root of a number, we the number with an index of 2. The base then become the principal square root.

In the same way, we find the cube root of a number by writing the number with an index of 3 and the base becomes the cube root of the given number.

For instance:

$64=8^2\implies 8=\sqrt{64}$

$64=4^3\implies 4=\sqrt[3]{64}$

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3 years ago

In ΔUVW, w = 44 cm, u = 83 cm and ∠V=141°. Find the area of ΔUVW, to the nearest square centimeter.

Tema [17]

Answer:

$Area \approx 1149\ cm^2$

Step-by-step explanation:

<u>Given that:</u>

ΔUVW,

Side w = 44 cm, (It is the side opposite to $\angle W$ )

Side u = 83 cm (It is the side opposite to $\angle U$ )

and ∠V=141°

Please refer to the attached image with labeling of the triangle with the dimensions given.

Area of a triangle with two sides given and angle between the two sides can be formulated as:

$A = \dfrac{1}{2}\times a\times b\times sinC$

Where a and b are the two sides and

$\angle C$ is the angle between the sides a and b

Here we have a = w = 44cm

b = u = 44cm

and ∠C= ∠V=141

Putting the values to find the area:

$A = \dfrac{1}{2}\times 44\times 83\times sin141\\\Rightarrow A = \dfrac{1}{2} \times 3652 \times sin141\\\Rightarrow A =1826 \times 0.629\\\Rightarrow A \approx 1149\ cm^2$

So, the <em>area </em>of given triangle to the nearest square centimetre is:

$Area \approx 1149\ cm^2$

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4 years ago