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worty [1.4K]
4 years ago
12

What is the Answer to four times four

Mathematics
2 answers:
34kurt4 years ago
7 0
16 is the answer to this question.
vichka [17]4 years ago
5 0

The answer is 16


Hope this helps :D

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V<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D%20%2A%202%5Cfrac%7B1%7D%7B3%7D" id="TexFormula1" title="\frac{3}{4} * 2
myrzilka [38]

Answer:

1\frac{3}{4}

Step-by-step explanation:

In order to find the answer, you first need to convert the mixed number (2 1/3) into a improper fraction and then multiply.

\frac{3}{4} \times2\frac{1}{3}

2\frac{1}{3} =3\times2=6+1=7=\frac{7}{3}

\frac{3}{4} \times\frac{7}{3}

3\times7=21

4\times3=12

=\frac{21}{12} =\frac{7}{4} =1\frac{3}{4}

=1\frac{3}{4}

Hope this helps.

7 0
3 years ago
Help pls I really need it
Talja [164]

Answer:

Infinite number of solutions

Step-by-step explanation:

when you solve for V, you notice that the term in "v" goes away, and you end up with a true statement:

2 = 2

This is a true statement no matter what values the variable V has, so it is true for all possible (infinite) values of "v".

8 0
3 years ago
Solve the system of linear equations by elimination.<br> -3.x – 5y = -7<br> -4x + 5y = 14
julia-pushkina [17]

Answer:

(- 1, 2 )

Step-by-step explanation:

Given the 2 equations

- 3x - 5y = - 7 → (1)

- 4x + 5y = 14 → (2)

Add the 2 equations term by term to eliminate y , that is

- 7x + 0 = 7

- 7x = 7 ( divide both sides by - 7 )

x = - 1

Substitute x = - 1 into either of the 2 equations and solve for y

Substituting into (1)

- 3(- 1) - 5y = - 7

3 - 5y = - 7 ( subtract 3 from both sides )

- 5y = - 10 ( divide both sides by - 5 )

y = 2

solution is (- 1, 2 )

8 0
3 years ago
Read 2 more answers
The following polygons are similar. Find x
Ray Of Light [21]

is 750.000 is your answer.

5 0
3 years ago
HELP HOW DO I SOLVE THE FOLLOWING? PLEASE HELP
levacccp [35]
f(x) = \sqrt[3]{2x - 1} \\f(14) = \sqrt[3]{2(14) - 1} \\f(14) = \sqrt[3]{28 - 1} \\f(14) = \sqrt[3]{27} \\f(14) = 3

f(x) = \sqrt[3]{2x - 1} \\f(-62) = \sqrt[3]{2(-62) - 1} \\f(-62) = \sqrt[3]{-124 - 1} \\f(-62) = \sqrt[3]{-125} \\f(-62) = -5

f(x) = \sqrt[3]{2x - 1} \\f(20) = \sqrt[3]{2(20) - 1} \\f(20) = \sqrt[3]{40 - 1} \\f(20) = \sqrt[3]{39}
4 0
3 years ago
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