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konstantin123 [22]
4 years ago
12

Kameryn types 75 words per minute and is just starting to write a term paper. Joe already has 510 words written and types at a s

peed of 60 words per minute for what numbers of minutes will kameryn have more words typed than joe?

Mathematics
1 answer:
NARA [144]4 years ago
7 0
Answer: Kameryn will have typed more words than Joe after 34 minutes

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If one three-digit number ( 0 cannot be a left digit) is chosen at random from all those that can be made from the following set
Oksana_A [137]

The probability of choosing a number that is not a multiple of 2 is P = 0.44

<h3 /><h3>How to find the probability?</h3>

We need to count the number of options for each digit.

  • For the first digit, we have 8 options {1, 2, 3, 4, 5, 6, 7, 8}
  • For the second digit, we have 9 options {0 ,1, 2, 3, 4, 5, 6, 7, 8}
  • For the third digit, we have 9 options {0 ,1, 2, 3, 4, 5, 6, 7, 8}.

The total number of combinations is the product between the numbers of options:

C = 8*9*9 = 648

If we want our number to not be a multiple of 2 then it must end in a odd digit, the combinations that meet that condition are:

  • For the first digit, we have 8 options {1, 2, 3, 4, 5, 6, 7, 8}
  • For the second digit, we have 9 options {0 ,1, 2, 3, 4, 5, 6, 7, 8}
  • For the third digit, we have 4 options {1, 3,  5, 7}.

C = 8*9*4 = 288

Then the probability of selecting a 3 digit number that is not a multiple of 2 is:

P = 288/648 = 0.44

If you want to learn more about probability, you can read:

brainly.com/question/251701

8 0
2 years ago
Which unit rate is equivalent to 13 miles per gallon? twenty-six miles over two gallons : two gallons over twenty-six miles thir
jeka94
Twenty-six miles over two gallons because the proportion for the original 13 miles to one gallon would be written 13/1 and, doing the same thing to the top and bottom, i multiplied by 2 and got 26/2
4 0
3 years ago
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What is 3 divided by 4/5
Veseljchak [2.6K]
The answer is 3.75 or 3 3/4
3 0
3 years ago
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Find the percent change from 48 to 228. Tell whether it is a percent increase or decrease. If necessary, round your answer to th
KIM [24]
228 - 48 = 180

180/48 = 3.75

Its increase 375%
7 0
3 years ago
1. Write the form of the partial fraction decomposition of the rational expression. Do not solve for the constants.
german

Answer:

Step-by-step explanation:

1.

To write the form of the partial fraction decomposition of the rational expression:

We have:

\mathbf{\dfrac{8x-4}{x(x^2+1)^2}= \dfrac{A}{x}+\dfrac{Bx+C}{x^2+1}+\dfrac{Dx+E}{(x^2+1)^2}}

2.

Using partial fraction decomposition to find the definite integral of:

\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}dx

By using the long division method; we have:

x^2-8x-20 | \dfrac{2x}{2x^3-16x^2-39x+20 }

                  - 2x^3 -16x^2-40x

                 <u>                                         </u>

                                            x+ 20

So;

\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x+\dfrac{x+20}{x^2-8x-20}

By using partial fraction decomposition:

\dfrac{x+20}{(x-10)(x+2)}= \dfrac{A}{x-10}+\dfrac{B}{x+2}

                         = \dfrac{A(x+2)+B(x-10)}{(x-10)(x+2)}

x + 20 = A(x + 2) + B(x - 10)

x + 20 = (A + B)x + (2A - 10B)

Now;  we have to relate like terms on both sides; we have:

A + B = 1   ;   2A - 10 B = 20

By solvong the expressions above; we have:

A = \dfrac{5}{2}     B =  \dfrac{3}{2}

Now;

\dfrac{x+20}{(x-10)(x+2)} = \dfrac{5}{2(x-10)} + \dfrac{3}{2(x+2)}

Thus;

\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)}

Now; the integral is:

\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx =  \int \begin {bmatrix} 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)} \end {bmatrix} \ dx

\mathbf{\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx =  x^2 + \dfrac{5}{2}In | x-10|\dfrac{3}{2} In |x+2|+C}

3. Due to the fact that the maximum words this text box can contain are 5000 words, we decided to write the solution for question 3 and upload it in an image format.

Please check to the attached image below for the solution to question number 3.

4 0
3 years ago
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