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konstantin123 [22]
3 years ago
12

Kameryn types 75 words per minute and is just starting to write a term paper. Joe already has 510 words written and types at a s

peed of 60 words per minute for what numbers of minutes will kameryn have more words typed than joe?

Mathematics
1 answer:
NARA [144]3 years ago
7 0
Answer: Kameryn will have typed more words than Joe after 34 minutes

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In 2015, the population of a small town in Florida is 95. If he population increases 15% every year, approximately what will the
vova2212 [387]

The population is increasing every year. so we use exponential growth function

y=a(1+r)^x

Where 'a' is the initial population

r is the rate of increase

x is the years

y is the final population

In 2015, the population of a small town in Florida is 95

Initial population a= 95

r= 15%= 0.15

x = 2023 - 2015 = 8 years

Plug in all the values and find out y

y=a(1+r)^x

y=95(1+0.15)^8

y = 290.607

The population in 2023 is 291

8 0
3 years ago
For a data set of weights? (pounds) and highway fuel consumption amounts? (mpg) of eight types of? automobile, the linear correl
liberstina [14]

Answer:

The correct option is;

Low

Step-by-step explanation:

Given that the P-value of the linear correlation = 0.001, we have that the P-value is a demonstration that a linear correlation that has a value in the range of the given correlation is ,most arguably very low

From the z-table, a P-value of 0.001 corresponds to a z-value of -3.09, we have that in a normal distribution since 95% of the scores have a z-score of between -2 and 2, the z-score of -3.09 is very distant from the mean and having a low value, whereby the P-value shows that the likelihood of finding another linear correlation that is as far from the mean as the given correlation  is very low.

8 0
3 years ago
Amber is starting a garden. She plants 2 flowers the first month. The next month, she plans three times more flowers (6 flowers)
Artist 52 [7]
This is a geometric progression problem. We can the general formula that can tell us how many flowers would be planted each month.
Let's write the terms that we know and see if we can find the pattern:

\begin{tabular}{lll}
Month & Number of flowers planted & Different form            \\
1     & 2                         & 2\cdot3^0 \\
2     & 6                         & 2\cdot3^1 \\
3     & 18                        & 2\cdot3^2 \\
4     & 54                        & 2\cdot3^3
\end{tabular}
\end{table}
The patern here is obvious. Let's write it down:
N=2\cdot3^{n-1}
This formula gives us a number of flowers planted in the n-th month.
6 0
2 years ago
What is the unit rate for 4543.08 km in 52.4 h? Enter your answer, as a decimal, in the box. km/h
sdas [7]
Plz mark me brainliest the answer is 86.7

hope this helps :)


8 0
3 years ago
Read 2 more answers
Identify the sequence graphed below and the average rate of change from n = 1 to n = 3.
dsp73

Answer:

The required sequence is a_n=20(\frac{1}{2})^{n-1}. The average rate of change from n = 1 to n = 3 is -7.5.

Step-by-step explanation:

From the given graph it is clear that the sequence is a GP because the all terms are half of their previous terms.

Here, a_2=10,a_3=5,a_4=2.5,a_5=1.25

r=\frac{a_3}{a_2}=\frac{5}{10}=\frac{1}{2}

The common ratio of GP is 1/2.

r=\frac{a_2}{a_1}

\frac{1}{2}=\frac{10}{a_1}

a_1=20

The first term of the sequence is 20.

The formula for sequence is

a_n=a(r)^{n-1}

Where a is first term and r is common difference.

The required sequence is

a_n=20(\frac{1}{2})^{n-1}

The formula for rate of change is

m=\frac{f(x_2)-f(x_1)}{x_2-x_1}

The average rate of change from n = 1 to n = 3 is

m=\frac{f(3)-f(1)}{3-1}

m=\frac{5-20}{3-1}

m=\frac{-15}{2}=-7.5

Therefore the required sequence is a_n=20(\frac{1}{2})^{n-1}. The average rate of change from n = 1 to n = 3 is -7.5.

8 0
3 years ago
Read 2 more answers
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