Kameryn types 75 words per minute and is just starting to write a term paper. Joe already has 510 words written and types at a s
peed of 60 words per minute for what numbers of minutes will kameryn have more words typed than joe?
1 answer:
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Fatima's claim is not supported by the table because, the distribution is skewed right, with a median of 0.4 field goal advantage.
From the table, the median position is calculated as:
The 0.2nd data falls in the 0.4 field goal category.
So, the median element is:
However, the distribution of the table are concentrated on the left.
This means that, the distribution is not uniform, instead it is skewed right.
A uniform distribution has a skewness of 0.
Hence, Fatima's claim is not supported by the table
Read more about distributions at:
Answer:
a. attached graph; zero real: 2
b. p(x) = (x - 2)(x + 3 + 3i)(x + 3 - 3i)
c. the solutions are 2, -3-3i and -3+3i
Step-by-step explanation:
p(x) = x³ + 4x² + 6x - 36
a. Through the graph, we can see that 2 is a real zero of the polynomial p. We can also use the Rational Roots Test.
p(2) = 2³ + 4.2² + 6.2 - 36 = 8 + 16 + 12 - 36 = 0
b. Now, we can use Briott-Ruffini to find the other roots and write p as a product of linear factors.
2 | 1 4 6 -36
1 6 18 0
x² + 6x + 18 = 0
Δ = 6² - 4.1.18 = 36 - 72 = -36 = 36i²
√Δ = 6i
x = -6±6i/2 = 2(-3±3i)/2
x' = -3-3i
x" = -3+3i
p(x) = (x - 2)(x + 3 + 3i)(x + 3 - 3i)
c. the solutions are 2, -3-3i and -3+3i
