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Aloiza [94]
4 years ago
13

Over what interval is the graph of f(x) = –(x + 8)2 – 1 decreasing?

Mathematics
2 answers:
Arturiano [62]4 years ago
7 0
F(x) = -(x + 8)² - 1 

<span>The function (not its graph) decreases on interval [-8, ∞). It is a quadratic function in vertex form. That form makes it easy to pick out the one extremum, where x equals -8. The leading coefficient is negative, so the extremum must be a maximum. The function decreases as x increases from there. </span>

<span>Notice that I include the value -8 in the interval. The function does not have instantaneous decrease at that value, but that is not what it means for a function to be decreasing over an interval. </span>

<span>Let a and b be any two values on [-8, ∞), such that a < b. </span>

<span>-8 ≤ a < b </span>

<span>Then f(a) > f(b). Therefore, function f is decreasing on interval [-8, ∞).</span>
IRISSAK [1]4 years ago
3 0

Answer:

A.

Step-by-step explanation:

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The statement that is true about the quadratic function is (b) the graph of the function is a parabola.

<h3>How to determine the true statements?</h3>

The quadratic function is given as

f(x) = x2 – 5x + 12

Rewrite as

f(x) = x² – 5x + 12

All quadratic functions are parabola

This means that option (b) is true

Set x = -10 to calculate f(-10)

So, we have

f(-10) = (-10)² – 5(-10) + 12

Evaluate

f(-10) = 162

This means that option (a) is false

Set x = 20 to calculate f(20)

So, we have

f(20) = (20)² – 5(20) + 12

Evaluate

f(20) = 312

This means that option (d) is false

Set x = 0 to calculate f(0)

So, we have

f(0) = (0)² – 5(2) + 12

Evaluate

f(0) = 12

This means that option (e) is false

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