Answer:
J'(2,-3), K'(4, -3) and L'(5,-2)
Step-by-step explanation:
The given triangle has vertices at J(2,3), K(4, 3) and L(5,2).
The transformation rule for a reflection in the x-axis is:
We substitute the points to obtain the coordinates of the image triangle J'K'L'
In other words, we negate the y-coordinates of triangle JKL to obtain the coordinates of J'K'L'
See attachment for graph.
, that is D
when multiplying like variables add the exponents
= =
Answer:
y = (x/(1-x))√(1-x²)
Step-by-step explanation:
The equation can be translated to rectangular coordinates by using the relationships between polar and rectangular coordinates:
x = r·cos(θ)
y = r·sin(θ)
x² +y² = r²
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r = sec(θ) -2cos(θ)
r·cos(θ) = 1 -2cos(θ)² . . . . . . . . multiply by cos(θ)
r²·r·cos(θ) = r² -2r²·cos(θ)² . . . multiply by r²
(x² +y²)x = x² +y² -2x² . . . . . . . substitute rectangular relations
x²(x +1) = y²(1 -x) . . . . . . . . . . . subtract xy²-x², factor
y² = x²(1 +x)/(1 -x) = x²(1 -x²)/(1 -x)² . . . . multiply by (1-x)/(1-x)
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The attached graph shows the equivalence of the polar and rectangular forms.
