So what is the question??? If I understand correctly....
y = 3x
Answer:
Step-by-step explanation:
4x -10y= 40
Let's rewrite this equation in the slope-intercept form (y= mx +c) so that we can obtain it's slope.
10y= 4x -40
Divide both side by 10:
The product of the gradients of perpendicular lines is -1.
⅖(gradient of line)= -1
Gradient of perpendicular line
Answer:
The remainder is: 3x+3
The quotient is: 1
Step-by-step explanation:
We need to divide
(3x^2 + 9x + 7) by (x+2)
The remainder is: 3x+3
The quotient is: 1
The solution is attached in the figure below.
So for CE, you add CD and DE together = CE.
4x+8+27=6x
4x+35=6x
4x-6x=-35
-2x=-35
x=17.5
Answer is the second one: CE=17.5
For ST, you just add SM and MT.
27+58=85
ST=85
Answer:
-2
Step-by-step explanation:
Given that:
A = (3, 4) ; B = (7, 6)
In triangle ABCD, AB and BC are Perpendicular lines :
Slope AB = Rise / Run = (y2 - y1) / (x2 - x1)
y2 = 6 ; y1 = 4 ; x2 = 7 ; x1 = 3
Slope AB = (6 - 4) / (7 - 3) = 2 / 4 = 1 / 2
To obtain the slope of BC:
RECALL:
product of the slope of 2 Perpendicular lines = - 1
Slope AB * Slope BC = - 1
1 / 2 * slope BC = - 1
Slope BC = - 1 ÷ 1/2
Slope BC = - 1 * 2/1
Slope BC = - 2
HENCE, slope of BC = - 2
